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3 years ago

What is the mode for presidents’ age when they begin their term?

Mathematics

2 answers:

BigorU [14]3 years ago

6 0

The answer to the question is 54.

Sonbull [250]3 years ago

3 0

The mode it the number that appears the most

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I need help asap!!!!!! pleaseeeee

sattari [20]

Find the area of the circle then, multiply that by the height of the cylinder.

Area of a circle = PI x r^2

Area = PI x 8^2 = 64PI

Volume = 64PI x 11 = 704PI in^3

3 0

3 years ago

One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.

Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 ) pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both = $ 39

I.e 2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = $\frac{39}{6}$ = $\frac{13}{2}$

∴ sw = $\frac{13}{2}$ × $\frac{3}{2}$

or, sw = $\frac{39}{4}$

Now, the ratio of the amount for swordfish to the amount of salmon = $\frac{\frac{39}{4}}{\frac{13}{2}}$

I.e The ratio = $\frac{6}{4}$

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0

3 years ago

Val walks 2 3/5 miles each day . Bill returns 10 miles once every 4 days . In 4 days, who covers the greatest distance

julia-pushkina [17]

Val by 4/10 walk longer

7 0

3 years ago

Sin (x/2)= √2- sin (x/2) solve for the exact solutions in the interval (0, 2π)

serg [7]

$sin\left( \frac{x}{2} \right)=\sqrt{2}-sin\left( \frac{x}{2} \right)\implies sin\left( \frac{x}{2} \right)+sin\left( \frac{x}{2} \right)=\sqrt{2}\implies 2sin\left( \frac{x}{2} \right)=\sqrt{2} \\\\\\ sin\left( \cfrac{x}{2} \right)=\cfrac{\sqrt{2}}{2}\implies sin^{-1}\left[ sin\left( \cfrac{x}{2} \right) \right]=sin^{-1}\left( \cfrac{\sqrt{2}}{2} \right) \implies \cfrac{x}{2}= \begin{cases} \frac{\pi }{4}\\\\ \frac{3\pi }{4} \end{cases} \\\\[-0.35em] ~\dotfill$