Answer:
The amount needed to pay off the loan after 4 years is $70,192
Step-by-step explanation:
When interest is compounded annually, total amount A after t years is given by:

where P is the initial amount (principal), r is the rate and t is time in years.
From the question:
P = $60,000
r = 4% = 0.04
t = 4

The amount needed to pay off the loan after 4 years is $70,192
If we divide the amount by four, we will get the amount that is paid yearly (70192/4 = 17548). $17,548 is paid yearly.
Answer:

Step-by-step explanation:
Think of a rational number as a fraction. The definition of a rational number is that it is the ratio of integers that, when divided, is either an integer, a decimal that terminates, or a decimal that repeats. 6/3 = 2 (6/3 is a rational number that divides to 2); 1/2 = .5 (1/2 is a rational number that divides to .5 which is a terminating decimal, meaning it ends); 1/3 = .33333333 (1/3 is a rational number that divides to .3333333 which is a repeating decimal). If we want to express 3.24 as a rational number, let's first put it into fraction form. The 4 in .24 is in the hundredths place, so as a fraction, .24 is 24/100. Check this on your calculator. Divide 24 by 100 and you get .24. So now what we have is 
Now express that mixed fraction as an improper and you're done. 3 times 100 is 300; 300 + 24 = 324. Put that back over 100 and your rational number is 324/100. Check that on your calculator, as well, just to see that it's true.
The best and the most correct answer among the choices provided by the question is the third choice. The table that best represents direct variation is:
<span>Input x 3 4 5
Output y 9 16 25
</span>I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
a) 675 000
b) 685 000
Step-by-step explanation:
The population of a town is 680 000 correct to the nearest 10 000.
a) To find it lower bound, we level of accuracy by 2 and then subtract from 680 000
The lower bound is:
680 000-5000=675,000
Therefore the least possible population of the town is 675 000
b) We repeat the same process to find the upper bound
680 000+5000=685,000