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creativ13 [48]
3 years ago
6

O quadro de 3^5 é = contas

Mathematics
1 answer:
FrozenT [24]3 years ago
4 0

3^5=243, good luck as far as I can understand the question

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Does 8 + 2(x−6) = −2 + 2x −2 have one solution, no solutions, or infinite solutions.
tia_tia [17]

Answer:

Infinite solutions

Step-by-step explanation:

All solutions are possible.

7 0
3 years ago
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The measure of an angle is 167°. What is the measure of its supplementary angle?
Anna007 [38]

Answer:

x=13

Step-by-step explanation:

Supplementary angles add to 180 degrees

x+167 = 180

Subtract 167 from each side

x+167-167= 180-167

x = 13

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3 years ago
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Given a polynomial f(x), if (x + 7) is a factor, what else must be true? f(0)=7 f(0)=-7 f(7)=0 f(-7)=0
Nataly [62]
F(-7)=0  

Because that makes the (x+7) factor equal zero and any other factor multiplied by zero also results in zero.
7 0
3 years ago
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<img src="https://tex.z-dn.net/?f=3%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%202%20%5Cfrac%7B1%7D%7B4%7D%20%20-%201%20%5Cfrac%7B1%7D%
Svetach [21]

Answer:

Step-by-step explanation:

Step 1: Convert into improper fractions

Step 2: Find  least common denominator and find equivalent fractions

Step 3 : Do the required operation

3\frac{1}{2}+2\frac{1}{4}-1\frac{1}{2}=\frac{7}{2}+\frac{9}{4}-\frac{3}{2}\\

Least common denominator of 2 , 4 = 4

   =\frac{7*2}{2*2}+\frac{9}{4}-\frac{3*2}{2*2}\\\\=\frac{14}{4}+\frac{9}{4}-\frac{6}{4}\\\\=\frac{14+9-6}{4}\\\\=\frac{17}{4}\\\\=4\frac{1}{4}

5 0
3 years ago
P(-3,6), Q(-3,-6) and R(6,-2) are the vertices of a triangle. Calculate the perimeter of this triangle.​
Eva8 [605]

Answer:

33.89

Step-by-step explanation:

the side lengths are the distances between the corner points of the triangle.

P and Q have the same x value, and they therefore create a side parallel to the y-axis. and it is easy to find the length of this side : it is just the difference of the y values.

PQ = 6 - (-6) = 6 + 6 = 12

QR and RP are trickier.

we need Pythagoras to calculate the length of the direct connection between these points as the Hypotenuse of the right triangles with the differences in x and in y values as the other sides.

QR :

QR² = (-3 - 6)² + (-6 - -2)² = (-9)² + (-4)² = 81 + 16 = 97

QR = sqrt(97) ≈ 9.848857802

RP :

RP² = (6 - -3)² + (-2 - 6)² = 9² + (-8)² = 81 + 64 = 145

RP = sqrt(145) ≈ 12.04159458

the perimeter/circumference of the triangle is the sum of all 3 sides

= 12 + sqrt(97) + sqrt(145) ≈ 33.89

3 0
3 years ago
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