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tangare [24]
2 years ago
9

Two number are in the ratio 5:4 if the smaller number is 32 find its greater number ​

Mathematics
1 answer:
Rina8888 [55]2 years ago
5 0
40, hope this helps :)
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Bess has $2.80 in quarters and dimes. The number of dimes is 7 less than the number of quarters. Find the number of quarters and
Nezavi [6.7K]

Answer:

3 dimes and 10 quarters

Step-by-step explanation:

If you add 7 dimes, then the number of dimes and quarters is the same, and the total increases to $3.50. A dime and a quarter have a value together of $0.35. Since there are equal numbers, the value $3.50 must be made up of some quantity of groups with a value of $0.35. That number of groups must be ...

... $3.50/$0.35 = 10

Thus, there are 10 quarters and 10-7 = 3 dimes.

_____

<em>Using an equation</em>

Let q represent the number of quarters. Then the amount Bess has is ...

... 0.10(q -7) +0.25q = 2.80

... 0.35q - 0.70 = 2.80

... 0.35q = 3.50 . . . . . add 0.70 . . . . . . . this should look familiar

... q = 3.50/0.35 = 10

4 0
3 years ago
-4/3x-6=-26 <br><br>A. -27<br>B. -15<br>C. 15<br>D. 27
JulsSmile [24]

Answer:

C. 15

Step-by-step explanation:

-4/3x-6=-26


The first step is to add 6 to each side

-4/3x-6+6=-26+6

-4/3x =-20  

Now multiply by -3/4 to isolate x.

-3/4 * -4/3x = -3/4 * -20

x = 60/4

x = 15

5 0
3 years ago
What is f(3)?<br> o 9<br> 0 -1<br> O 1<br> O 9
arlik [135]

Answer:

C.

Step-by-step explanation:

f(3) is referring to 3 on the left side and it is beside 1 which is on the left so it's 1.

4 0
3 years ago
Can someone please help?
lesya [120]
It is 7/8 the last one
8 0
2 years ago
Read 2 more answers
FURTHER MATHEMATICS Use determinants to solve the systems of equation:
maw [93]

Answer:

Step-by-step explanation:

\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\

\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\

\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\

\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\

\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.

8 0
3 years ago
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