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3 years ago

Which equation is an identity?

2 answers:

3 0

3w + 8 - w = 4w - 2(w - 4)
is an identity
3w-w + 8 = 4w - 2w + 8
2w + 8 = 2w + 8
2w - 2w = 8 - 8
0 = 0
zero equal to zero implies that any value of w satisfies the statement 3w + 8 - w = 4w - 2(w - 4) hence it is an identity.

adoni [48]3 years ago

3 0

3w + 8 - w = 4w - 2(w - 4) is the identity.

- Prodixy ☕

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Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi

maks197457 [2]

Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ $x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is $x=\frac{-31+29}{2}=-1$

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is $y=\frac{8+-10}{2}=-1$

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed $\frac{2}{3}$ of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ $x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and $y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is $x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11$

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is $x=\frac{(8)(1)+(-1)(2)}{2+1}=2$

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

3 0

3 years ago

Help please much appreciated

larisa [96]

The answer is a.........

6 0

3 years ago

Read 2 more answers

Anyone know the area?

Elina [12.6K]

Answer: The area of the triangle is: " 8.5 cm² " ;

or, write as: " 8 $\frac{1}{2}$ cm² " .
_______________________________________________________
Explanation:
_________________________________________________________
The formula {"equation"} for the area of a triangle is:

A = ( $\frac{1}{2}$ ) * b * h ;

in which: A = area;
b = base;
h = [perpendicular] height;
___________________________________
{also, can be written as: " A = (b * h) / 2 " .}.
______________________________________
Solve for the area, "A" ; by plugging in the known values shown in the figure (image attached):
______________________________________
base, "b" = 13 cm ;
[perpendicular] height, "h" = 5 cm ;
______________________________________
A = (b * h) / 2 ;

= (13 cm * 5 cm) / 2 ;

= [ (13 * 5) cm²] / 2 ;

= 65 cm² / 2 ;

A = " 8.5 cm² " ; or, write as: " 8 $\frac{1}{2}$ cm² " .
_________________________________________________________
Answer: " 8.5 cm² " ; or, write as: " 8 $\frac{1}{2}$ cm² " .
_________________________________________________________
The area of the triangle is: " 8.5 cm² " ;

or, write as: " 8 $\frac{1}{2}$ cm² " .
_________________________________________________________

5 0

3 years ago

Q: An experiment was conducted to study the effect of increasing the dosage of a certain barbiturate on sleeping

aleksklad [387]

Answer:

Step-by-step explanation:

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3 years ago

Triangle JKL was dilated with the origin as the center of dilation to create triangle ′′′.J′K′L′. The triangle was dilated using

zmey [24]

Answer:

KL = 5.25

LJ = 6

Step-by-step explanation:

i don’t know the first one

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3 years ago