F (x) = -3x+5x^2+8 has blank roots.
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Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
=
But this distance needs to be betweem 50 & 60
So
Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
=
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
Sorry it is a bit messy but the answer is right
Note that if 
, then 
, and so we can collapse the system of ODEs into a linear ODE:
which is a pretty standard linear ODE with constant coefficients. We have characteristic equation
so that the characteristic solution is
Now let's suppose the particular solution is
. Then
and so
Thus the general solution for
is
and you can find the solution
by simply differentiating .
which is a pretty standard linear ODE with constant coefficients. We have characteristic equation
so that the characteristic solution is
Now let's suppose the particular solution is
and so
Thus the general solution for
and you can find the solution