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3 years ago

Help with this question please

Mathematics

2 answers:

dem82 [27]3 years ago

5 0

Answer:

gallons = dependent

minutes = independent

Step-by-step explanation:

independent variable = the variable being manipulated/changed

dependent variable = the variable being changed as a result

gallons = dependent (of the minutes of running water)

minutes = independent (affecting the gallons)

vodomira [7]3 years ago

5 0

Gallons - dependent
Minutes - independent

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Given that a rectangle has a length of 5/2x + 10 with a width of 5/2x + 5, formulate an expression to represents the area of the

stepan [7]

Answer:

Step-by-step explanation:

L = ⁵/₂x + 10

W = ⁵/₂x + 5

A = L•W

A = (⁵/₂x + 10)(⁵/₂x + 5)

A = ⁵/₂x•⁵/₂x + ⁵/₂x•5 + 10•⁵/₂x + 10•5

A = ²⁵/₄x² + ²⁵/₂x + ⁵⁰/₂x + 50

A = ²⁵/₄x² + ⁷⁵/₂x + 50

Or if yoy mean:

L = 5/(2x) + 10

W = 5/(2x) + 5

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3 years ago

After looking through different hotel options, Gabriela and Luis decided to estimate a budget of $1200 for hotel costs. They wan

MatroZZZ [7]

Answer:

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Step-by-step explanation:

6 = amount of nights

240=tax

c = total cost a night

1200 = budget

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3 years ago

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in a circle a 60 sector has an area of 25 pi square feet. what is the circumference? leave your answer in terms of pi and in sim

belka [17]

The area of the sector is given by the equation,
A = πr²(x / 360°)
where x is the number of degrees in the figure.
25π ft² = (πr²)(60/360)
The value of r is 12.25 ft. Then, we use this value to calculate for the circumference of the sector.
C = 2πr(x/360)
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3 years ago

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

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3 years ago

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Digiron [165]

Answer:

x = -1

Step-by-step explanation:

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