May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
You wanna find a common denominator so put the problem like this
3 1/3.< You wanna take 3 (denominator)
And times it
By 5 then you wanna take the 5. - 2 2/5.< (deniminator) and times it by 3.
____ Your common denominator is 15
now it will look like this
3 1/15
-2 2/15
———-
Now subtract. You will need to borrow 1 from 3 since you cant subtract 2 by 1 so the 3 will become a 2 and the 1 will be come 11 and here you can subtract so this will be your answer.
2 11/15
-2 2/15
-———-
0 9/15
Thats your official answer 9/15 hope I helped :)
Answer:
1) maldava y despota
2) pequenos
Step-by-step explanation:
Answer:
66 squares are in the circle.
Answer:
40 units
Step-by-step explanation:
A=hbb
2=8·10
2=40
