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NikAS [45]
3 years ago
10

Suppose you want to click up- and down-arrows on a "control" to change the value of the product price in cell C7. What form cont

rol (two word answer) would you use?
Computers and Technology
1 answer:
Julli [10]3 years ago
8 0

Answer:

Spin button.

Explanation:

Spread sheet applications are softwares used to analyze and manipulate data for clean and easy data presentation.

It is composed of columns or fields and rows or records to make a worksheet of a workbook in the application. Each box on the worksheet is called a cell.

Data can be inputted directly to a cell or with functions and formulas and with the form control feature.

Form control is use to specify the range of input to use in cells for easy data input. The spin button of the form control is used to input data by pressing the up and down arrow key on the keyboard.

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xxTIMURxx [149]
Most likely depends on the situation
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3 years ago
For this project you will write a Java program that will run a simple math quiz. Your program will generate two random integers
ElenaW [278]

Answer:

Here is the JAVA program:

import java.util.Scanner;   //to accept input from user

public class FunWithBranching {   //class name

   public static void main(String[] args) {  //start of main function

   Scanner input = new Scanner(System.in);  //creates Scanner object

   System.out.print("Enter your name: "); //prompts user to enter name

   String userName = input.nextLine();  //stores the name

   System.out.print("Welcome " + userName + "! Please answer the following questions:\n");   //prompts user to answer the questions

   int randomOperand1 =  (int)(20 * Math.random()) + 1;  //generates random number for operand 1 (1-20)

   int randomOperand2 =  (int)(20 * Math.random()) + 1;  //generates random number for operand 2 (1-20)

   int randomAdd = randomOperand1 + randomOperand2;  //performs addition of two random numbers and stores result in randomAdd

   int randomMul = randomOperand1 * randomOperand2;  //performs multiplication of two random numbers

   int randomDiv = randomOperand1 / randomOperand2;  //performs division of two random numbers

   int randomMod = randomOperand1 % randomOperand2;  //performs modulo of two random numbers

   int correctAns = 0;  //stores number of correct answers

   System.out.print(randomOperand1 + " + " + randomOperand2 + " = ");  //displays random number + random number

   int AdditionGuess = input.nextInt();   //reads the answer of addition from user and stores it in AdditionGuess

   if (AdditionGuess == randomOperand1 + randomOperand2) {  //if the user answer is correct

   System.out.println("Correct!");  //displays correct

   correctAns++;  //adds 1 to the count of correctAns every time the user gives correct answer of addition

 } else {  //if user answer is incorrect

   System.out.println("Wrong!");  //displays wrong

   System.out.println("The correct answer is " + randomAdd);   }  //displays the correct answer of addition

   System.out.print(randomOperand1 + " * " + randomOperand2 + " = ");  //displays random number * random number  

   int MultiplicationGuess = input.nextInt();   //reads the answer of multiplication from user and stores it in MultiplicationGuess

 if (MultiplicationGuess == randomOperand1 * randomOperand2) {  //if the user answer is correct

     System.out.println("Correct!");  //displays correct

     correctAns++;  //adds 1 to the count of correctAns every time the user gives correct answer of multiplication

 }else{  //if user answer is incorrect

       System.out.println("Wrong!");  //displays wrong

       System.out.println("The correct answer is " + randomMul);   }  //displays the correct answer of multiplication

   System.out.print(randomOperand1 + " / " + randomOperand2 + " = ");  //displays random number / random number  

   int DivisionGuess = input.nextInt();   //reads the answer of division from user and stores it in DivisionGuess

   if (DivisionGuess == randomOperand1 / randomOperand2) {  //if the user answer is correct

       System.out.println("Correct!");  //displays correct

       correctAns++;   //adds 1 to the count of correctAns every time the user gives correct answer of division

       }else{  //if user answer is incorrect

           System.out.println("Wrong!");  //displays wrong

           System.out.println("The correct answer is " + randomDiv);     }  //displays the correct answer of division

      System.out.print(randomOperand1 + " % " + randomOperand2 + " = ");  //displays random number % random number  

       int ModGuess = input.nextInt();  //reads the answer of modulo from user and stores it in ModGuess

           if (ModGuess == randomOperand1 % randomOperand2) {  //if the user answer is correct

           System.out.println("Correct!");  //displays correct

           correctAns++;   //adds 1 to the count of correctAns every time the user gives correct answer of modulo

           }else{  //if user answer is incorrect

               System.out.println("Wrong!");  //displays wrong

               System.out.println("The correct answer is " + randomMod);    }  //displays the correct answer of modulo

double percentage = correctAns * 25;   //computes percentage

System.out.println("You got " + correctAns + " correct answers.");   //display number of correct answers given by user

System.out.println("That's " + percentage + "%!");         }  } //displays percentage

Explanation:

The program is well explained in the comments mentioned with each line of code. The screenshot of the output is attached.

3 0
3 years ago
How many passes will it take to find the five in this list?
Savatey [412]

Answer:

1 im prety sure

Explanation:

5 0
3 years ago
Read 2 more answers
Given a typical magnetic hard drive with five platters, answer the following:
Nataly_w [17]

Answer:

Given the number of platters =5

A. Hence, the number of recording surface =10

B. number of read-write heads =10

C. Number of arms holding the read-write heads = 10

Explanation:

We know that number of recording surface = 2 *( number of platters)

= 2*5=10

And the number of read-write heads = number of recording surface= 10

Also, number of arms holding the read-write head = one for each read-write head= 10

And hence, the above answer.

5 0
3 years ago
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Kamila [148]
I did- but I don’t anymore
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2 years ago
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