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NikAS [45]
3 years ago
10

Suppose you want to click up- and down-arrows on a "control" to change the value of the product price in cell C7. What form cont

rol (two word answer) would you use?
Computers and Technology
1 answer:
Julli [10]3 years ago
8 0

Answer:

Spin button.

Explanation:

Spread sheet applications are softwares used to analyze and manipulate data for clean and easy data presentation.

It is composed of columns or fields and rows or records to make a worksheet of a workbook in the application. Each box on the worksheet is called a cell.

Data can be inputted directly to a cell or with functions and formulas and with the form control feature.

Form control is use to specify the range of input to use in cells for easy data input. The spin button of the form control is used to input data by pressing the up and down arrow key on the keyboard.

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Who played a leading role in perfecting movable type for printing?
vaieri [72.5K]
Johannes Gutenberg, although there are various examples of movable type from China (and Korea, to a lesser extent).
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4 years ago
A mother age is formed by reversing the two digits of daughters age. If the mother is 18 years older than daughter and sum of th
Gwar [14]
I'm not absolutely positive that my answer is correct... but here's what I got...

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4 0
3 years ago
Write a program that accepts a number as input, and prints just the decimal portion.
Olegator [25]

<u>Answer:</u>

<em>There are 2 ways to do extract the decimal part: </em>

<u>Explanation:</u>

  • <em>First method using number  </em>

<em>int main() { </em>

<em>  double num = 23.345; </em>

<em>  int intpart = (int)num; </em>

<em>  double decpart = num - intpart; </em>

<em>  printf(""Num = %f, intpart = %d, decpart = %f\n"", num, intpart, decpart); </em>

<em>} </em>

  • <em>Second method using string: </em>

<em>#include <stdlib.h> </em>

<em>int main() </em>

<em>{ </em>

<em>    char* inStr = ""123.4567"";          </em>

<em>    char* endptr;                       </em>

<em>    char* loc = strchr(inStr, '.'); </em>

<em>    long mantissa = strtod(loc+1, endptr); </em>

<em>    long whole = strtod(inStr, endptr);  </em>

<em>    printf(""whole: %d \n"", whole);      </em>

<em>    printf(""mantissa: %d"", mantissa);   </em>

<em>} </em>

8 0
3 years ago
Read 2 more answers
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ser-zykov [4K]

Answer:

<h3><em>SWITCH</em><em> </em><em>CASE</em><em>:</em></h3>

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<em>☆</em><em> </em><em>SWITCH</em><em> </em><em>STATEMENT</em><em> </em><em>EVALUATES</em><em> </em><em>ONLY</em><em> </em><em>CHARACTER</em><em> </em><em>《</em><em>OR</em><em> </em><em>》</em><em>INTEGER</em><em> </em><em>VALUE</em><em>. </em>

<em>☆</em><em> </em><em>IT</em><em> </em><em>USING</em><em> </em><em>SINGLE</em><em> </em><em>EXPRESSION</em><em> </em><em>FOR</em><em> </em><em>MULTIPLE</em><em> </em><em>CHOICES</em><em>. </em>

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<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELP</em><em>.</em><em>.</em><em>.</em><em>.</em><em /><em /><em />

7 0
3 years ago
Can someone please help me in answering this!?! <br> The language is C++
Llana [10]

Here is a somewhat cryptic solution that works:

#include <algorithm>

#include <cstdlib>

using namespace std;

void q(char c, int count)

{

for (int i = 0; i < count; i++) {

 putchar(c);

}

}

void p(int b1, int plusses)

{

q(' ', b1);

q('+', plusses);

}

int main()

{

for (int i = -3; i <= 3; i++)

{

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 p(6-pl, pl);

 i == 0 ? p(0, 6) : p(6, 0);

 p(0, pl);

 putchar('\n');

}

getchar();

}


5 0
3 years ago
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