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Burka [1]
3 years ago
6

Suppose that the splits at every level of quicksort are in the proportion 1 − α to α where 0 < α ≤ 1/2 is a constant. Show th

at the minimum depth of a leaf in the recursion tree is approximately
Computers and Technology
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

Explanation:

The minimum depth occurs for the path that always takes the smaller portion of the

split, i.e., the nodes that takes α proportion of work from the parent node. The first

node in the path(after the root) gets α proportion of the work(the size of data

processed by this node is αn), the second one get (2)

so on. The recursion bottoms

out when the size of data becomes 1. Assume the recursion ends at level h, we have

(ℎ) = 1

h = log 1/ = lg(1/)/ lg = − lg / lg

Maximum depth m is similar with minimum depth

(1 − )() = 1

m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )

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ppose we have a Rectangle class that includes length and width attributes, of type int, both set by the constructor. Define an e
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Answer:

Check the explanation

Explanation:

#include <bits/stdc++.h>

using namespace std;

class Rectangle{

  public:

      int length;

      int breadth;

      Rectangle(int l,int b){

          length = l;

          breadth = b;

      }

      int area(){

          return length*breadth;

      }

      int perimeter(){

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      }

      bool equals(Rectangle* r){

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          if (r->length == length && r->breadth == breadth)

              return true;

          // They have the same area

          if (r->area() == area())

              return true;

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          if (r->perimeter() == perimeter())

              return true;

          // They have the same shape-that is, they are similar.

          if (r->length/length == r->breadth/breadth)

              return true;

          return false;

      }

};

int main(){

  Rectangle *r_1 = new Rectangle(6,3);

  Rectangle *r_2 = new Rectangle(3,6);

  cout << r_1->equals(r_2) << endl;

  return 0;

}

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The correct debugged code is attached below

<h3>What is a leap year </h3>

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Hence we can conclude that the correct debugged code is attached below.

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