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Fynjy0 [20]
3 years ago
14

.....help me please

Mathematics
1 answer:
Virty [35]3 years ago
3 0
Your answer would be A
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Write a linear equation to represent the line shown on the graph
sveticcg [70]

Answer:

y=-3x+4

Step-by-step explanation:

it's negative bc the slope is going from left to right. you just have to do rise over run to find the slope.

7 0
3 years ago
a. Show that the system of rational expressions is closed under addition, or give an example showing the contrary.
otez555 [7]
A "rational expression" is a fraction in which the numerator and the denominator are both polynomials. The sum of two such expressions will always produce another such expression, viz., 
<span>p(x)/q(x) + r(x)/s(x) = [p(x)s(x) + q(x)r(x)] / [q(x)*s(x)]. </span>
<span>The numerator and denominator of the sum will both be polynomials when fully expanded</span>
7 0
2 years ago
3 erasers cost $4.41. Write a proportion that would solve for the cost of 4 erasers.
Bess [88]

Answer:

$5.88

Step-by-step explanation:

3 erasers ⇒ $4,41

4 erasers ⇒ $A

A = 4 erasers * $4.41 / 3 erasers

A = $ 5.88

7 0
2 years ago
Read 2 more answers
Mr. Haley is leaning a ladder against the side of his house to repair the roof.
Ludmilka [50]

Answer:

20 feet

Step-by-step explanation:

Remember the Pythagorean theorem,

x^2 + y^2 = n^2

in this case

x= 16

y = 12

so substitute back into the equation

16^2 + 12^2 = n^2

256 + 144 = n^2

400 = n^2

sqrt ( 400) = n

20 = n

8 0
3 years ago
Evaluate the limit, if it exists.<br> lim (h - &gt; 0) ((-7 + h)^2 - 49) / h
baherus [9]

Expand everything in the limit:

\displaystyle\lim_{h\to0}\frac{(-7+h)^2-49}h=\lim_{h\to0}\frac{(49-14h+h^2)-49}h=\lim_{h\to0}\frac{h^2-14h}h

We have h approaching 0, and in particular h\neq0, so we can cancel a factor in the numerator and denominator:

\displaystyle\lim_{h\to0}\frac{h^2-14h}h=\lim_{h\to0}(h-14)=\boxed{-14}

Alternatively, if you already know about derivatives, consider the function f(x)=x^2, whose derivative is f'(x)=2x.

Using the limit definition, we have

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h=\lim_{h\to0}\frac{(x+h)^2-x^2}h

which is exactly the original limit with x=-7. The derivative is 2x, so the value of the limit is, again, -14.

4 0
3 years ago
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