Need help with this problem Ty

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

7 0

Sin(pi/6) would be appropriate as that is 1/2

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What is the distance between A and B? Round your answer to the nearest hundredth.

Reika [66]

An extension of the Pythagorean Theorem results in what is the so-called "distance formula".

d^2=(x2-x1)^2+(y2-y1)^2, in this case you have points (-2,4) and (2,0) so:

d^2=(2--2)^2+(0-4)^2

d^2=4^2+(-4)^2

d^2=16+16

d^2=2*16

d=√32 units

d=√(2*16)

d=4√2 units

d≈5.66 units (to nearest hundredth of a unit)

6 0

3 years ago

Need help with I ready math

vovangra [49]

Answer:

5(P - 1.00) + 3(P - 0.75)

Step-by-step explanation:

Cost of a package in store A = $P

Discount offered at store A = $1.00

Price paid per package at store A = Cost of a package in store A - Discount offered at store A

= P - 1.00

Cost of a package in store B = $P

Discount offered at store B = $0.75

Price paid per package at store B = Cost of a package in store B - Discount offered at store B

= P - 0.75

Total cost of 5 packages at store A and 3 packages at store B = 5(P - 1.00) + 3(P - 0.75)

4 0

3 years ago

Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to of itself the result is a 15. The mod

Bess [88]

X+x=15 combine like terms on left side

2x=15 divide both sides by 2

x=7.5

4 0

3 years ago

Read 2 more answers

A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores

KengaRu [80]

Answer:

The 95% confidence interval for the difference of means is (7.67, 16.33).

The estimate is Md = 12.

The standard error is sM_d = 2.176.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1 (this year's sales), of size n1=36 has a mean of 53 and a standard deviation of 12.

The sample 2 (last year's sales), of size n2=49 has a mean of 41 and a standard deviation of 6.

The difference between sample means is Md=12.

$M_d=M_1-M_2=53-41=12$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12^2}{36}+\dfrac{6^2}{49}}\\\\\\s_{M_d}=\sqrt{4+0.735}=\sqrt{4.735}=2.176$