Answer:
![\large\boxed{D.\ 2x^2y\sqrt[5]{7xy^3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BD.%5C%202x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D%7D)
Step-by-step explanation:
![\sqrt[5]{224x^{11}y^8}\\\\=\sqrt[5]{(32)(7)x^{5+5+1}y^{5+3}}\\\\\text{use}\ a^na^m=a^{n+m}\\\\=\sqrt[5]{(2^5)(7)x^5x^5x^1y^5y^3}\\\\\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=\sqrt[5]{2^5}\cdot\sqrt[5]{x^5}\cdot\sqrt[5]{x^5}\cdot\sqrt[5]{y^5}\cdot\sqrt[5]{7xy^3}\\\\\text{use}\ \sqrt[n]{a^n}=a\\\\=2\cdot x\cdot x\cdot y\cdot\sqrt[5]{7xy^3}\\\\=2x^2y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D%5C%5C%5C%5C%3D%5Csqrt%5B5%5D%7B%2832%29%287%29x%5E%7B5%2B5%2B1%7Dy%5E%7B5%2B3%7D%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5Ena%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D%5Csqrt%5B5%5D%7B%282%5E5%29%287%29x%5E5x%5E5x%5E1y%5E5y%5E3%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Ccdot%5Csqrt%5Bn%5D%7Bb%7D%5C%5C%5C%5C%3D%5Csqrt%5B5%5D%7B2%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7Bx%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7Bx%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7By%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7B7xy%5E3%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%5C%5C%5C%5C%3D2%5Ccdot%20x%5Ccdot%20x%5Ccdot%20y%5Ccdot%5Csqrt%5B5%5D%7B7xy%5E3%7D%5C%5C%5C%5C%3D2x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Answer:
x = 55
Step-by-step explanation:
For PQ and RS to be parallel then
∠ACQ = ∠RDB ( Alternate exterior angles ), thus
3x - 65 = 2x - 10 ( subtract 2x from both sides )
x - 65 = - 10 ( add 65 to both sides )
x = 55
I think the answer is 90 degrees
Answer:
4th graph
6th graph
3rd graph
Step-by-step explanation:
Linear = y = x + 3
it is 4th graph
when you substitute x = 0 y is 3
and when y = 0 x is -3
Quadratic = y = 3x^2
It is 6th graph
for both positive and negative values of x, y is rapidly increasing
Exponential = y = 3^x
it is 3rd graph
for x = 0 y value is 1 because 3^0 = 1
for positive values of x, y is exponentially rising
for negative values of x it is nearly almost touches zero
