18+30=48
48+40=88
88+40=128
128+50=178
Thats all i found so far in the pattern
30,40,40,50
then it drops
by 140 then adds by 30..
I dont know how else to explain it
Answer:
75°
Step-by-step explanation:
Let's find the size of x°
BCFE has four sides so the sum of its angles sizes is 360°.
● CBE + 110 + 110 + CFE = 360
CFE is equal to 65° since they have the same vertex
● CBE + 220 + 65 = 360
● CBE + 285 = 360
● CBE = 360-285
● CBE = 75
CBE and x° have the same size since they share the same vertex.so:
● x° = 75°
Answer:
f(x) = -8
Step-by-step explanation:
f(x) = x² + 2x – 8
f(x) = (-2)² + 2(-2) – 8
f(x) = (-2)² + 2(-2) – 8
f(x) = 4 + (-4) – 8
f(x) = 4 – 4 – 8
f(x) = 0 – 8
f(x) = -8
I hope this helps
Answer:
A)82.02 mi
B) 18.7° SE
Step-by-step explanation:
From the image attached, we can see the angles and distance depicted as given in the question. Using parallel angles, we have been able to establish that the internal angle at egg island is 100°.
A) Thus, we can find the distance between the home port and forrest island using law of cosines which is that;
a² = b² + c² - 2bc Cos A
Thus, let the distance between the home port and forrest island be x.
So,
x² = 40² + 65² - 2(40 × 65)cos 100
x² = 1600 + 4225 - (2 × 2600 × -0.1736)
x² = 6727.72
x = √6727.72
x = 82.02 mi
B) To find the bearing from Forrest Island back to his home port, we will make use of law of sines which is that;
A/sinA = b/sinB = c/sinC
82.02/sin 100 = 40/sinθ
Cross multiply to get;
sinθ = (40 × sin 100)/82.02
sin θ = 0.4803
θ = sin^(-1) 0.4803
θ = 28.7°
From the diagram we can see that from parallel angles, 10° is part of the total angle θ.
Thus, the bearing from Forrest Island back to his home port is;
28.7 - 10 = 18.7° SE