HELP PLS’ Suppose you roll a die. Find the probability of the given event. Simplify your answer.

Which choice represents the expression below as a single exponential

Lostsunrise [7]

Answer:

D

Step-by-step explanation:

When multiplying numbers with the same base but different exponents, add the exponents together.

4 0

2 years ago

Please help me solve this

Ira Lisetskai [31]

I’m sorry I do not know the other person was rude

6 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

What is y+2= (-3) (x-4)

TEA [102]

Y=-3x+10 is your awnser

3 0

3 years ago

Read 2 more answers

What numbers form a right triangle

Cloud [144]

let's recal the pythagorean theorem, where c² = a² + b², namely, the largest number squared is equal to the sum of the two smaller ones squared.

well, we can just start by say in A, looking the smaller sides, 3 and √9, if we squared both and add them up, do they give the largest one of √18?

$\boxed{A} \\\\ 3^2+(\sqrt{9})^2 = (\sqrt{18})^2\implies 9+9 =18\qquad \textit{\Large\checkmark} \\\\\\ \boxed{B}\\\\ 3^2+4^2=5^2\implies 9+16=25\implies 25=25\qquad \textit{\Large\checkmark} \\\\\\ \boxed{C}\\\\ 7^2+7^2=(\sqrt{98})^2\implies 49+49=98\implies 98=98\qquad \textit{\Large\checkmark}$

so they all apply.

8 0

2 years ago