1. Divide it into a triangle and a rectangle
2. To solve the area of the rectangle which is (length times width) do 2x9 = 18
3. To solve the area of the triangle which is (length times width divided by 2) do 2x4/2 =4
4. Area = 18 + 4, 22 square units
a) Is the twitch - initial positive twitch or sudden movement, which is what
makes the car jolt into action.
b) is the acceleration - graph shows the acceleration and
deceleration of the car.
c) is the velocity - starts at 0 and increases until the car
travels at its right speed.
d) is the position - assuming that the car is going on only
one direction. This graph is the only one that does not go back to the x-axis.
You need to use the conditional probability formula:
P(A|B) = P(A∩B) / P(B)
Key:
P(A|B): Probability of A given B
P(A∩B): Probability of A and B
If we say A is the event that the train arrives on time and B is the event that the train leaves on time, then according to the information:
P(B) = 0.4
P(A∩B) = 0.28
Just insert into the formula:
P(A|B) = 0.28 / 0.4 = 0.7
(or 70% as a percentage).
Answer:
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-6+8+9=2x+3
11=2x+3
8=2x
x=4