Answer:
A
Step-by-step explanation:
O = 26.6
P is a right angle so:
P = 90
angles PQO = 180
To determine Q: triangle total - (P + O)
180 - (90 + 26.6)
180 - 116.6 = 63.4
Q = 63.4
To determine side lengths: a^2 + b^2 = c^2
4^2 + b^2 = c^2
*Variable c is always hypotenuse*
Need more information so find either b or c through SOH, CAH, TOA
SOH: sine = opposite/hypotenuse
CAH: cos = adjacent/hypotenuse
TOA: tan = opposite/adjacent
tan26.6/1 = b/4
Cross multiply
1 × b = 4 × tan26.6
b = 4tan26.6
b = 2.003050791
b is about 2
b = PQ
PQ = 2
Plug b value into pythagorean theorm
4^2 + 2^2 = c^2
16 + 4 = c^2
20 = c^2
square root of 20 = square root of c^2
4.47213.... = c
c is about 4.47
c = QO
A
Working:
Tan(angle)=opposite/adjacent
Tan60 = x/7root3
x=7root3 x Tan60
Enter in calculator
x=21
It would probably be B because it said between -30 and 130
Answer:
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Step-by-step explanation:
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Here is your answer
Money saved on each successive day is-
$3, &5, $7....
Clearly it forms an AP,
where
a1= 3
common difference, d= 2
n=20
So,
using formula
Tn= a1+(n-1)d
T20= 3+(20-1)2
= 3+ 19×2
= 3+ 38
=41
So, money saved on August 20= $41
Sum of money saved upto August 20 =
n/2 (a1+T20)
= 20/2 (3+41)
= 10× 44
= $440
HOPE IT IS USEFUL
