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svp [43]
3 years ago
10

A roller coaster starts from a deck at an elevation of 20 feet above the ground. On the first hill it climbs 83 feet and then dr

ops 42 feet. On the second hill the coaster climbs 128 feet and then drops 90 feet. How far above the ground is the coaster after the second hill?
Mathematics
2 answers:
Zielflug [23.3K]3 years ago
7 0
I would say 99 feet.  An elevation of 20 feet above the ground is the starting point.  Then as the coaster rises 83 feet, you add 20 + 83 = 103 feet.  Then it drops 42 feet.  103 - 42 = 61 feet.  Then it rises 128 feet on the second hill.  61 + 128 = 189 feet.  Finally, it drops 90 feet.  189 - 90 = 99 feet above the ground after the second hill.
Simora [160]3 years ago
3 0
Initially started 20 feet from the ground . 
Went uphill 83 feet. 
So: 20 + 83 = 103. The coaster is 103 ft above at this point. 

Went down 42 feet 
So: 103 - 42 = 61. 

Went up 128 feet
So: 61 + 128 = 189

Finally, went down 90 feet
So: 189 - 90 = 99

99 ft above ground.
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Answer:

0.69473828 radians east of north.

Step-by-step explanation:

Interpreting the information given on a Cartesian plane, the position of the ship will be (1,0) and that of the rock will be (7,5). Connecting the point (1,0) and (7,5) with a line and dropping a perpendicular line from point (7,5) to the x-axis to intersect the x-axis at (7,0), will form a right-triangle with base length 6 units and a height of 5 units.

<u>Finding the base length from points (1,0) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-1)²

d= √6²

d=6 units

<u>Finding the height from points (7,5) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-7)² + (0-5)²

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So you now have a right triangle with base length 6 units and height 5 units.

To get the bearing of rock from ship position you apply the formula for tangent of an angle

Tan Ф = length of opposite side/length of adjustment side

TanФ=5/6

Tan Ф =0.83333333333

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slega [8]

I am pretty sure the answer would be (a)

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8_murik_8 [283]

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