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Bad White [126]
3 years ago
11

What is the answers for number 31

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0
I think the answer may be A 

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Each side of a equilateral triangle measures 9cm. Find the height, h, of the triangle. ...Please show work :] thanks
zaharov [31]
Break it up into 2 triangles. base is 4.5, hypotenuse is 9
4.5^2+b^2=8120.25+b^2=81b^2=60.75
h=7.794228634059948
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Suppose that you want to model the height of a rider on a Ferris wheel as a function of time. The amplitude of the function you
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The amplitude of the function you use as a model should be equal to <span>d. the radius of the Ferris wheel. The amplitude should be half the difference between the highest (maximum) and lowest (minimum) points which is half of the diameter of the circle. It is known that half of the diameter is the radius of a circle.</span>
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3 years ago
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Beth writes a number that shows 60 parts out of 100
dangina [55]

Answer:

60/100               orrrrrrrrrrrrrrrr 6/10

Step-by-step explanation:

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2 years ago
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Suppose you were considering going bungee jumping, but would only go if the mean breaking strength of the cord was greater than
serg [7]

Answer:

Type II error will occur when we conclude that the mean breaking strength of the cord is smaller than or equal to 250 pounds but in actual it was not true.

Step-by-step explanation:

We are given that you are considering going bungee jumping, but would only go if the mean breaking strength of the cord was greater than 250 pounds.

If the mean breaking strength of the cord is greater than 250 pounds, the bungee cord will not break.

<u><em>Let </em></u>\mu<u><em> = mean breaking strength of the cord</em></u>

So, Null Hypothesis, H_0 : \mu \leq 250 pounds  

Alternate Hypothesis, H_A : \mu > 250 pounds

Here, null hypothesis states that the mean breaking strength of the cord was smaller than or equal to 250 pounds.

On the other hand, alternate hypothesis states that the mean breaking strength of the cord was greater than 250 pounds.

Now, Type II error states the Probability of accepting null hypothesis given the fact that it was false or Probability of accepting the false hypothesis.

SO, <u>according to our question, Type II error </u>will occur when we conclude that the mean breaking strength of the cord is smaller than or equal to 250 pounds but in actual it was not true and he mean breaking strength of the cord was greater than 250 pounds.

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3 years ago
Solve for y. 2(3y – 6) = 24 A. 36 B. 6 C. −6 D. −36
Juliette [100K]

Answer:

The correct answer choice would be : B.6

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3 years ago
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