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qaws [65]
3 years ago
8

Please help me out ?

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0
An obtuse triangle is formed if there is an angle that has a measure of more than 90 degrees. You can determine if an obtuse angle is formed by two sides of a triangle if it meet this condition:

Let a and b be two sides of a triangle and c is the longest side:
a^{2}  +  b^{2}  \ \textless \   c^{2}

So taking your given:

10^{2}  +  15 ^{2} < c^{2}
100 + 225   < c^{2}
325  <  c^{2}

To get the smallest possible number, just get the square root of both sides:

\sqrt{325} < \sqrt{c^{2} }
  18.03  < c

So your smallest possible whole number is 19
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\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\&#10;-------------------------------\\\\&#10;sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}&#10;\\\\\\&#10;sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)&#10;\\\\\\&#10;\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}

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\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\&#10;-------------------------------\\\\&#10;sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}&#10;\\\\\\&#10;sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o&#10;\\\\\\&#10;\theta=\cfrac{-8.05}{2}\implies \theta=-4.025

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there
7 0
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