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qaws [65]
3 years ago
8

Please help me out ?

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0
An obtuse triangle is formed if there is an angle that has a measure of more than 90 degrees. You can determine if an obtuse angle is formed by two sides of a triangle if it meet this condition:

Let a and b be two sides of a triangle and c is the longest side:
a^{2}  +  b^{2}  \ \textless \   c^{2}

So taking your given:

10^{2}  +  15 ^{2} < c^{2}
100 + 225   < c^{2}
325  <  c^{2}

To get the smallest possible number, just get the square root of both sides:

\sqrt{325} < \sqrt{c^{2} }
  18.03  < c

So your smallest possible whole number is 19
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What is the inverse of the function f(x) = 2x - 10?
EastWind [94]
F-1(x)=x/2+5
explanation:
5 0
3 years ago
he sum of the first two terms of a G.P is 27 whereas the sum of the second and third term is 54. Find the first term and the com
viktelen [127]

Answer:

{ \tt{sum =  \frac{a(r {}^{n - 1} )}{n - 1} }} \\ 27 =  \frac{a(r {}^{2 - 1} )}{2 - 1}  \\ { \bf{27 = ar -  -  - (i)}} \\  \\ 54 =  \frac{a( {r}^{3 - 1} )}{3 - 1}  \\ { \bf{108 = a {r}^{2} -  -  - (ii) }} \\ { \tt{(ii) \div (i) : }} \\ r =  \frac{108}{27}  \\ { \bf{common \: ratio = 4}} \\ { \bf{first \: term =  \frac{27}{4}  }}

7 0
3 years ago
A study is performed in San Antonio to determine whether the average weekly grocery bill per five-person family in the town is s
bogdanovich [222]

Answer:

No, the sample evidence is not statistically significant (P-value = 0.125).

To reject the null hypothesis, the P-value has to be smaller than the significance level, so the significance level to reject the null hypothesis has to be 0.125 or higher.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

Then, the null and alternative hypothesis are:

H_0: \mu=131\\\\H_a:\mu\neq 131

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=133.474.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=11.193.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{11.193}{\sqrt{50}}=1.583

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{133.474-131}{1.583}=\dfrac{2.474}{1.583}=1.563

The degrees of freedom for this sample size are:

df=n-1=50-1=49

This test is a two-tailed test, with 49 degrees of freedom and t=1.563, so the P-value for this test is calculated as (using a t-table):

P-value=2\cdot P(t>1.563)=0.125

As the P-value (0.125) is bigger than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

8 0
2 years ago
PLEASE HURRY ILL GIVE BRAINLIEST!!!!!!!!!!!
QveST [7]
The one that isn’t rationals is B.
8 0
3 years ago
2. If (300) (30,000) = 9 x 10m, then m =
Rufina [12.5K]
(300) (30,000) = 9 x 10m
9,000,000 = 90m
divide by 90
100,000 = m
6 0
2 years ago
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