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forsale [732]
3 years ago
6

WILL GIVE BRAINIEST!!! Polygon ABCDE is shown on the coordinate grid. What is the perimeter, to the nearest hundredth of a unit,

of polygon ABCDE?

Mathematics
1 answer:
Georgia [21]3 years ago
3 0

The perimeter of polygon ABCDE is 20.31 units.

Step-by-step explanation:

Step 1; First we plot points A, B, C, D and E on the graph. Coordinates are A (-3, 2), B (1, 2), C (3, -1), D(0, -3) and E (-4, -3). We need to find the distance between the 5 sides of the polygon i.e AB, BC, CD, DE, and AE.

Step 2; The sides AB and AE can be measured directly as they are horizontal lines. The x coordinate for A is -3 while for B it is 1, so distance is 1-(-3) = 4 units. The x coordinate for E is -4 while for D it is 0, so the distance is 0- (-4) = 4 units.

Step 3; To find the distances of BC, CD, and AE we use the formula

Distance = √ (x2 - x1)² + (y2 - y1)².

Distance between B (1, 2) and C (3, -1) where B is (x1, y1) and C is (x2, y2).

Distance = √(3 - 1)² + (-1 -2)² = √4 + 9 = √13 = 3.605 units.

Distance between C (3, -1) and D (0, -3) where C is (x1, y1) and D is (x2, y2).

Distance = √(0 -3)² + (-3 -(-1))² = √9 + 4 = √13 = 3.605 units.

Distance between A (-3, 2) and E (-4, -3) where D is (x1, y1) and E is (x2, y2).

Distance = √(-4 -(-3))² + (-3 -2)² = √1 + 25 = √26 = 5.099 units.

Step 2; The parameter of this polygon is given by summing the lengths of the 4 sides.

Parameter = AB + BC + CD + DE + AE = 4 + 3.605 + 3.605 + 4 + 5.099 = 20.309 units. This is rounded off to 20.31 units.

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