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3 years ago

What is -6x+3(4x-5)=21

Mathematics

2 answers:

Fynjy0 [20]3 years ago

5 0

-15 i think if not u just got to use the quadratic formula.

Talja [164]3 years ago

4 0

I don't exactly know what you're trying to solve but x=6

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Let p: x < −3 Let q: x > 3 What is represented by p ∨ q?

anastassius [24]

Answer:

p v q = x < -3 or x > 3

Step-by-step explanation:

We are given

p: x < -3

q: x > 3

and we need to find p v q

v symbols represents disjunction and in simple terms it is called "or"

So, p v q represents either p holds or q holds

So, p v q = x < -3 or x > 3

8 0

3 years ago

Read 2 more answers

What is b for x^2 -6x-3=0

andrew-mc [135]

Answer:

x = 3 + 2 sqrt3 Or 3 - 2 sqrt 3

Step-by-step explanation:

8 0

3 years ago

Please help me I have been stuck on this question for ages

Finger [1]

Answer:28 green and 35 red

Step-by-step explanation:

Given

If there are r red counter and g green counter then

Probability of drawing a green counter is $P(g)=\frac{4}{9}$

and $P(g)=\frac{\text{No of g counter}}{\text{Total no of counter}}$

Thus $\frac{\text{No of g counter}}{\text{Total no of counter}}=\frac{4}{9}$

$\frac{g}{g+r}=\frac{4}{9}$

$\Rightarrow 9g=4g+4r$

$\Rightarrow 5g=4r\quad \ldots(i)$

Also if 4 red and 2 green counter is added the probability of drawing a green counter is

$P(g)=\frac{10}{23}=\frac{\text{No of g counter}}{\text{Total no of counter}}$

$\Rightarrow \frac{10}{23}=\frac{g+2}{g+2+r+4}$

$\Rightarrow \frac{10}{23}=\frac{g+2}{g+r+6}$

$\Rightarrow 10g+10r+60=23g+46$

$\Rightarrow 10r+14=13g\ quad \ldots(ii)$

Substitute the value of g in equation (ii)[/tex]

$\Rightarrow 10\times \frac{5}{4}g+14=13g$

$\Rightarrow \frac{25}{2}g+14=13g$

$\Rightarrow g=28$

Therefore $r=35$

Thus there 28 green counter and 35 red counter

6 0

3 years ago

Look at pic 10 points

koban [17]

Answer:

120

Step-by-step explanation: 10 x 12 = 120 m. Hope this helps

7 0

3 years ago

Use a strategy to find the product 16 × 400

Crazy boy [7]

Answer:

enter it in a calculator, and you get 6400

7 0

3 years ago