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Mashcka [7]
2 years ago
13

Alan, Bill, and Calvin are playing a game with collectible cards. At the moment, Alan has 11 less than 2.5 times the number of c

ards Bill has. Calvin has 1 more than 1.5 times the number of cards Bill has.
Mathematics
1 answer:
oksian1 [2.3K]2 years ago
3 0

Answer:

50

Step-by-step explanation:

I'm sorry but your missing the questions but I found a close answer! Let A be the number of cards Alan has B be the number of cards Bill has C be the number of cards Calvin has Alan had 11 less than 2 1/2 times the number of cards bill has. is 2.5 Alan is 2.5 of bill has minus 11 A=2.5B -11 Calvin has 1 more than 1 1/2 times the number of cards bill has. is 1.5 Calvin is 1.5 of bill has plus 1 C=1.5B + 1 Alan and Calvin have the same number of cards So A=C WE plug in A  and C equations and solve for B 2.5B -11 = 1.5B + 1 (subtract 1.5B on both sides) 1B -11 = 1 (Add 11 on both sides) B = 12 If Alan and Calvin have the same number of cards, the number bill has is 12 The number of cards Alan and Calvin each have is 19 Total cards = 12 + 19 + 19 = 50 If Alan, bill, and Calvin have all the cards in the deck then the deck has 50 cards.

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y+1 =(3/4)x+9/4

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3 years ago
Marshall uses 10 ounces of pineapple
garik1379 [7]

Answer:

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3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20-%20%284x%20-%2015%29%20%5Cgeqslant%20-%209%283%20%2B%20x%29" id="TexFormula1" title=" - (4
Kay [80]

- (4x - 15) \geqslant  - 9(3 + x) \\  - 4x + 15 \geqslant  - 27 - 9x \\  - 4x + 9x \geqslant  - 27 - 15 \\ 5x \geqslant  - 42 \\ x \geqslant  - 8 \dfrac{2}{5}


21 + x > 2( - 2 - 5x) + 6x \\ 21 + x >  - 4 - 10x + 6x \\ x + 10x - 6x >  - 4 - 21 \\ 5x >  - 25 \\ x >  - 5

Hope this helps. - M
5 0
3 years ago
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