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Flauer [41]
3 years ago
5

You draw a card at random from a deck that contains 333 black cards and 777 red cards. What is \text{P(draw a black card})P(draw

a black card)start text, P, left parenthesis, d, r, a, w, space, a, space, b, l, a, c, k, space, c, a, r, d, end text, right parenthesis? If necessary, round your answer to 222 decimal places.
Mathematics
1 answer:
enot [183]3 years ago
6 0

Answer:

The probability of picking a black card at random, from a deck with 3 black cards and 7 red ones is 0.3.

Step-by-step explanation:

We will assume that we have 3 black cards and 7 black cards, for a total of 10 cards. Since we are taking one card at random, we can assume that each card is equally likely to be drawn. We have the following event A: The drawn card is a black. We will find the probability of A as counting the number of outcomes that make A to occur and divide it by the total number of possibilities. We are drawing one card, so we have 10 possibilities to be picked. Out of those 10, only 3 cards are black, hence we have 3 possibilites of picking a black card.

Then,

P(A) = 3/10 = 0.3.

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A taxi fare has a fixed charge of 1.75 and an additional charge 0.45 per mile. A fare for m miles is 13.90. Which equation could
Pavel [41]

Answer:

The answer is 27 miles and option b will give that.

Step-by-step explanation:

1.75 + 0.45m = 13.90

m = (13.90 - 1.75) / 0.45

m = 27 miles

Hope this helped

3 0
3 years ago
What is the temperature, in degrees Fahrenheit, shown on the thermometer to the nearest integer? Enter your integer answer in th
Illusion [34]
It’s negative 4 because the scale shows there is 4 lines
8 0
2 years ago
What is the answer to 12x^7 over 3x
Darina [25.2K]
Simple, what you're basically doing is simplifying,

\frac{ 12x^{7} }{3x}

well, you have 3x and you have 12x^{7}

12/3=4

and you can "cancel" out an x, making your answer,

4x^{6}.
8 0
3 years ago
Use the cross product property to solve each equation: 5/7 = x/9
enot [183]

Answer:

x = 45/7

Step-by-step explanation:

\frac{5}{7} =\frac{x}{9}

Here, you can more easily see what the fractions look like.

In order to cross-multiply, you have to multiply 5 with 9, and 7 with x.

45 = 7x

Then, you isolate x by dividing 7 on both sides:

45/7 = x

Hope I helped :)

8 0
3 years ago
The number of ways in which 4 squares can be chosen at random on a chess board such that they lie on a diagonal line?.
wariber [46]

The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

<h3>What are permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

It is given that:

On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:

The required number of ways:

= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))

= 2[2[ 1 + 5 + 15+35] + 70]

= 364

Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ4

5 0
1 year ago
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