We know that two complements add up to 90.
Let's call the smaller angle x and the larger y.
3x = y
x + y = 90
We can use simple substitution.
x + 3x = 90
4x = 90
x = 22.5
Then, since we know that 3x=y, we can find the larger angle.
3*22.5 = 67.5
Rise over run. as time increases the temperature rises. starting at 8am and -2°f.
At 12pm the temperature rose to 4°f.
that's a difference of 4 hours and 6 degrees. for every hour, it rose 1.5 degrees. the slope is 1.5/1
Using distributive property, we get:
3x-9=0
3x=9
x=3
So, x=3. Now that was easy, huh? :)
Answer:
Step-by-step explanation:
Let's see how well I can explain this.
is the same as a 30 degree angle which is in quadrant 1. If you picture the unit circle, right in the center of it is the origin. If you draw a straight line from 30 degrees and through the center (the origin), you will automatically "connect" with the reference angle of 30 (this is true for ALL angles on the unit circle). This puts us in quadrant 3. In quadrant 3, x is negative and so is y. So the terminal point of the reference angle for 30 degrees has the same exact values, but both of them are negative (again, because both x and y are negative in quadrant 3). I can't see your choices but the one you want looks like this:

Answer:
Nethan made 8 rose bouquets and 6 daffodil bouquets.
Nethan only has enough flowers to make at most 20 rose or daffodil bouquets total.
Let x represents the number of more rose bouquets.
Let y represents the number of more daffodil bouquets.
The maximum bouquets that can be made = 20
And the number of bouquets made are = 14
So, additional bouquets are = 
In equation form we can show like :

or 
or 
Putting values of x as 0,2,4 and 6 we get:
When x = 0 then y = 6
When x = 2 then y = 4
When x = 4 then y = 2
When x = 6 then y = 0
You can see the graph attached.