Question

Select the relations that are functions.

Answer 1

Answer:

Depending on how the input of each function defined,

• The first choice $\left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace$,
• The third choice $\left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace$
• The fourth choice $\left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace$

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

• be defined for all elements in the domain, and
• map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element $a$ from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be $\lbrace a,\, 6, \, C\rbrace$. Similarly, the domain for the third and fourth relations should be $\lbrace 1,\, 2, \, 3\rbrace$ and $\lbrace a,\, b, \, c\rbrace$