Answer:
see below for the graph
Step-by-step explanation:
The desired graph has two y-intercepts and one x-intercept. It is not the graph of a function.
Here's one way to get there.
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Start with the parent function y = |x| and scale it down so that it has a y-intercept of -1 and x-intercepts at ±1.
Now, it is ...
f(x) = |x| -1
We want to scale this vertically by a factor of -5. this puts the y-intercept at +5 and leaves the x-intercepts at ±1.
Horizontally, we want to scale the function by an expansion factor of 3. The transformed function g(x) will be ...
g(x) = -5f(x/3) = -5(|x/3| -1) = -5/3|x| +5
This function has two x-intercepts at ±3 and one y-intercept at y=5. By swapping the x- and y-variables, we can get an equation for the graph you want:
x = -(5/3)|y| +5
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<em>Comment on this answer</em>
Since there are no requirements on the graph other than it have the listed intercepts, you can draw it free-hand through the intercept points. It need not be describable by an equation.
A) The signs of the first derivative (g') tell you the graph increases as you go left from x=4 and as you go right from x=-2. Since g(4) < g(-2), one absolute extreme is (4, g(4)) = (4, 1).
The sign of the first derivative changes at x=0, at which point the slope is undefined (the curve is vertical). The curve approaches +∞ at x=0 both from the left and from the right, so the other absolute extreme is (0, +∞).
b) The second derivative (g'') changes sign at x=2, so there is a point of inflection there.
c) There is a vertical asymptote at x=0 and a flat spot at x=2. The curve goes through the points (-2, 5) and (4, 1), is increasing to the left of x=0 and non-increasing to the right of x=0. The curve is concave upward on [-2, 0) and (0, 2) and concave downward on (2, 4]. A possible graph is shown, along with the first and second derivatives.
Answer given in the picture above.
Simple..you get the RAtional answer of...
-2w-2
Thus, your answer.
Answer:
C
Step-by-step explanation:
As x goes up, y goes down