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4 years ago

15

The algebraic process you use to isolate a variable in order to find what values, numbers, etc. will make an equation true. You

_____ the equation.

1 answer:

Mnenie [13.5K]4 years ago

3 0

Solve is the certain answer, not "check the equation" silly. Now, I must solve some more problems on Brainly :)

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Please help help help!!!

torisob [31]

Answer:

The other X is -3.

Step-by-step explanation:

5 0

3 years ago

What is the length of FG¯?

liberstina [14]

FG is mid-segment

so

FG = (AB + DC)/2

FG = (15+37)/2

FG = 52/2

FG = 26

Answer FG = 26 ft

6 0

4 years ago

Item 16 The variables x and y vary directly. Use the values to find the constant of proportionality, k. Then write an equation t

masya89 [10]

Answer:

k = 2

x = 2y

Step-by-step explanation:

If variables x and y vary directly, this is expressed as;

x ∝ y

x = ky

k is the proportionality constant

Let's assume the value of x and y since we are not given;

x = 20

y = 10

Substitute

20 = k(10)

10k = 20

k = 20/10

k = 2

Hence the constant of proportionality is 2

Substitute i=k = 2 into the equation x = ky

x = 2y

Hence an equation that relates x and y is x = 2y

<em>Note that the values here are assumed value, you can use the same method for any values of x and y</em>

4 0

3 years ago

Solve for x in the equation x squared + 2 x + 1 = 17.

Whitepunk [10]

Answer:

x = negative 1 plus-or-minus StartRoot 17 EndRoot

Step-by-step explanation:

Given:

$x^2+2x+1=17$

We need to solve for x.

$x^2+2x+1=17 \ \ \ \ equation\ 1$

First we will solve L.H.S

Factorizing the equation we get;

$x^2+2x+1\\=x^2+x+x+1\\=x(x+1)+1(x+1)\\=(x+1)(x+1)\\=(x+1)^2$

Now Things which are equal to the same thing are also equal to one another. Since

$x^2+2x+1=17$

$x^2+2x+1=(x+1)^2$

then, according to the law of transitivity,

$(x+1)^2=17$

Now, applying the Square Root Principle we get:

$\sqrt{(x+1)^2} =\sqrt{17}$

Now Square root and square gets cancelled.

$x+1=\sqrt{17} \\x=-1+\sqrt{17}$

Since a square root has two values, one positive and the other negative.

$x=-1\±\sqrt{17}$

Hence Final Answer is $x=-1\±\sqrt{17}$ .

5 0

4 years ago

Read 2 more answers

Please help me find out what the question marks are

quester [9]

Question a

g(x) times $\sqrt{x-5}=\sqrt{x^2-5}$
divide both sides by √(x-5)
$g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}$
$g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}$
$g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$

question b
$g(x) \space\ times \space\ 1+\frac{1}{x}=x$
divide both sides by 1+1/x
$g(x)=\frac{x}{1+\frac{1}{x}}$
times by x/x
$g(x)=\frac{x^2}{x+1}$

question c
$\frac{1}{x} \space\ times \space\ f(x)=x$
times both sides by x
$f(x)=x^2$

question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
wait
ah, ya
basically
$|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})$
so f(x)=√x

a. $g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$
b. $g(x)=\frac{x^2}{x+1}$
c. $f(x)=x^2$
d. $f(x)=\sqrt{x}$

3 0

4 years ago

Read 2 more answers