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2 years ago

I NEED HELP

Mathematics

1 answer:

Naddik [55]2 years ago

7 0

The answer could be B not sure hold up don’t pick yet

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Solve for x, −2 (4x+4) −3x − 2 = 34 help needed, thanks!

Arada [10]

Hey there!

The answer to your question is $-2 \frac{3}{11}$

$-2(4x+4) - 3x -2= 34$ Write the equation

$-8x - 8 - 3x - 2 = 34$ Distribute -2

$-11x-10 = 34$ Combine like terms

$-11x = 24$ Add 10 to both sides

$-2 \frac{3}{11}$ Divide both sides by -11

Hope it helps and have a great day!

4 0

3 years ago

Four employees of Papa Tony's Pizza are cleaning up at the end

Lady bird [3.3K]

Answer:

10.75

Step-by-step explanation:

43 divided by 4

8 0

3 years ago

For the given function f(x) = 2.6x + 4.3, x is the number of years since 2000 and y (or f(x)) is the percent of students taking

dsp73

Answer:

in 2005, 17.3 percent of students are taking at least one online course

Step-by-step explanation:

f(5) = 2.6(5) +4.3 = 17.3

The definition of the function f(x) tells you that f(5) = 17.3 means 5 years after the year 2000, 17.3 percent of students are taking at least one online course.

7 0

3 years ago

Evaluate 5xyz + 3y for x=2.5, y=12, and z=4

Reika [66]

Answer:

636

Step-by-step explanation:

5xyz+3y

5(2.5)(12)(4)+3(12)

(12.5)(48)+36

600+36

636

8 0

3 years ago

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago