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Alex Ar [27]
4 years ago
9

When you eat salmon for dinner, your digestive system will break down that food

Biology
1 answer:
zimovet [89]4 years ago
6 0

Answer:   c. Amino Acids

Explanation:

Food is chemically and mechanically broken down into smaller particles like building blocks, the smallest of these are a basic unit called monomers. In the <em>stomach</em>, the enzyme pepsin breaks proteins, like those found in salmon, into smaller peptides by splitting the peptide bonds holding the proteins together. The <em>duodenum</em> processes these newly-formed peptide chains or polypeptides, into smaller ones, through the enzyme action of elastase, trypsin and chymotrypsin; these are produced in the pancreas. Peptidases convert these fragments into amino acid monomers for absorption into the bloodstream via the small intestines.

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One might suggest that transposons are more likely to insert in noncoding regions of the genome because they are
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Answer:

they are evolutionary neutral

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Transposons are genetic mobile elements that move into the genome by means of cut-paste and copy-paste mechanisms. In consequence, transposons are known to produce mutations in the inserted genomic sequences.

Non-coding DNA regions have been generally assumed to be evolutionary neutral, it means that they might resist genetic polymorphisms (such as, for example, those caused by the insertion of transposon elements) and don't have direct effects on the phenotype of the organism. However, it is important to note that recent evidence supports the idea that noncoding sequences play important regulatory roles, thereby mutations in these genomic regions may have a deleterious effect on the organism.

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What was observed to happen to the frequency of small-beak-depth g. fortis on an island when a large-beak-depth competitor was i
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The first observation was that, natural selection might itself be variable because it is dependent with the different seasons the environment have. Second, the frequency of small-beak depth Geospiza fortis became lesser on an island when a large-beak-depth was introduced because the large-beak-depth species has greater survival rate especially during dry season were they can eat larger and harder seeds as compare to the small-beak-depth birds.

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Read 2 more answers
You will be given a stock solution of BSA protein with a BSA concentration of 2 mg/mL. (Here, "mgimL is the concentration unit i
Korolek [52]

Answer: See table in the attachment.

Explanation: 1) The <u>Parallel</u> <u>Dilution</u> <u>Formula</u> is given by:

C_{1}.V_{1} = C_{2}.V_{2}

where:

C is concentration

V is volume

For the given data, index 1 represents the concentration and volume of the stock solution and index 2, the concentration and volume of the diluted solution. For example:

V_{1} = \frac{C_{2}.V_{2}}{C_{1}}

V_{1} = \frac{0.1.100}{2} = 5 μL

V_{1} = \frac{0.15.100}{2} = 7.5 μL

V_{1} = \frac{0.2.100}{2} = 10 μL

V_{1} = \frac{0.25.100}{2} = 12.5 μL

V_{1} = \frac{0.3.100}{2} = 15 μL

V_{1} = \frac{0.35.100}{2} = 17.5 μL

V_{1} = \frac{0.2.100}{2} = 20 μL

Substituing C_{2} for each concentration given and find each volume needed.

The results is shown in the second column of the table.

2) The stock and total volume is determined. So, to calculate the volume of water needed:

V_{H_{2}O} = V_{total} - V_{stock}

V_{H_{2}O} = 100 - 5 = 95 μL

V_{H_{2}O} = 100 - 7.5 = 92.5 μL

V_{H_{2}O} = 100 - 10 = 90 μL

V_{H_{2}O} = 100 - 12.5 = 87.5 μL

V_{H_{2}O} = 100 - 15 = 85 μL

V_{H_{2}O} = 100 - 17.5 82.5 μL

V_{H_{2}O} = 100 - 20 = 80 μL

As shown in the third column of the table.

Download pdf
3 0
3 years ago
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