Answer:
Time in the air t₁ = 7 s
Time in the sea t₂ = 5 s
Step-by-step explanation:
We will use the equation: v = d/t , where:
v is the average speed,
d the distance traveled, and
t time doing the trip
From v = d/t ⇒ d = v*t
Therefore, if we call t₁ time in the air, and t₂ time in the sea, according to problem statement, we have:
t₁ + t₂ = 12 (1)
16*t₁ + 3*t₂ = 127 (2)
A two equation system, from equation (1) we get
t₂ = 12 - t₁
And by substitution in equaton (2)
16*t₁ + 3 * ( 12 - t₁ ) = 127
16*t₁ + 36 - 3*t₁ = 127
13*t₁ = 91
t₁ = 91 /13
t₁ = 7 s
And t₂ = 12 - 7
t₂ = 5 s
Answer:
65
Step-by-step explanation:
if they are similar their sides are in proportion and so are the corresponding medians
to see their corresponding sides line up the names of the triangles
N Q Z
⇵⇵⇵
C B K
BK / QZ = 45/27 ; substitute whit what you see in the picture
(4x+1) / (2x+7) = 45/27 ; cross multiply
27( 4x+1) = 45( 2x+7) ; distribute
108x + 27 = 90 x + 315; subtract 90x and 27 from both sides
108x -90x = 315 -27; combine like terms
18x = 288; divide both sides by 18
x=16
BK = 4* 16 +1 = 65
Answer:
no lo se :l
Step-by-step explanation: