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Lunna [17]
3 years ago
14

A 97% confidence interval for the mean of a population is to be constructed and must be accurate to within 0.3 unit. A prelimina

ry sample standard deviation is 1.4. The smallest sample size n that provides the desired accuracy is
Mathematics
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

The sample size will be "102.5494 \sim 102". A further explanation is given below.

Step-by-step explanation:

Let the sample size will be:

= n

The given values are:

Standard deviation,

= 1.4

ME,

= 0.3

As we know,

⇒ n=(Z \frac{a}{2}\times \frac{SD}{E})^2

On putting the estimated values, we get

⇒    =(2.17\times \frac{1.4}{0 .3})^2

⇒    =(\frac{3.038}{0.3})^2

⇒    =102.5494 \sim 102

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Use an x&y to graph the function below f(x) = - (x+2)^3+1
kenny6666 [7]

Answer: f=26

Step-by-step explanation: x^2+6x^2+12x+7/x= 26

3 0
3 years ago
Which of the numbers 285, 629, 5490, 15708, 43695 are divisible by 3 but not by 9?
Ne4ueva [31]

Answer:

285

Step-by-step explanation:

285÷3=95

285÷9=31.6666

3 0
2 years ago
Read 2 more answers
Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

8 0
3 years ago
I need help asap !! I will mark Brainly!
Reil [10]

<u>Answer: x-axis</u>

<u><em>Explanation</em></u>:

  • x-axis: it is the horizonzontal axis
  • x-coordinates: it is the x-value of a point in reference to the x-axis
  • y-axis: it is the vertical axis
  • y-coordinates: it is the y-value of a point in reference to the y-axis

Hope that helps!

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2 years ago
Help me with math, please
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Number 28 would be y= -52x+148
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