1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vagabundo [1.1K]
2 years ago
12

Find the average value of f over the given rectangle. f(x, y) = 3x2y, r has vertices (−5, 0), (−5, 3), (5, 3), (5, 0). g

Mathematics
1 answer:
AlekseyPX2 years ago
6 0
\dfrac{\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_R\mathrm dx\,\mathrm dy}
\dfrac{\displaystyle\int_{y=0}^{y=3}\int_{x=-5}^{x=5}3x^2y\,\mathrm dx\,\mathrm dy}{\displaystyle\int_{y=0}^{y=3}\int_{x=-5}^{x=5}\mathrm dx\,\mathrm dy}
\displaystyle\frac1{10}\left(\int_{y=0}^{y=3}y\,\mathrm dy\right)\left(\int_{x=-5}^{x=5}x^2\,\mathrm dx\right)
\dfrac{75}2
You might be interested in
a family has five children. the probability of having a girl is 1/2. whats probability of having at leasr 4 girls g'
Dima020 [189]

Answer:

Probability of having at least 4 Girls

= 0.6875

Step-by-step explanation:

Probability of having at least 4 Girls is 1-probability of having exactly 3 girls

Total number of children= 5 = N

Probability of having a girl p = 0.5

Probability of not having a girl q= 0.5

X= 3

Probability of at least 4 girls is given by

Probability= NCX(p)^x(q)^(N-x)

Probability = 5C3(0.5)^3(0.5)^(5-3)

Probability = 5C3(0.5)^3(0.5)^2

Probability= 5!/3!2!(0.5)^3(0.5)^2

Probability= 10(0.125)(0.25)

Probability= 0.3125

Probability of having at least 4 Girls

= 1- 0.3125

= 0.6875

7 0
2 years ago
Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. q^2+7q
viva [34]
Stay in school q^2*7q cuh
8 0
2 years ago
Which figure is NOT a polygon?
alexdok [17]

Answer:

A.

Hope It Help

Step-by-step explanation:

Brainliest please

5 0
2 years ago
Read 2 more answers
Tim worker is doing his budget. He discovers that the average miscellaneous expense is $45.00 with a standard deviation of $16.0
Marianna [84]
So what's the question??

3 0
2 years ago
Writethecoordinatesoftheverticesafteradilationwithascalefactorof 1 5 ,centeredattheorigin. y x -10 10 -10 10 0 S T U S(5, -10) →
densk [106]

Answer:

The answer is below

Step-by-step explanation:

Write the coordinates of the vertices after a dilation with a scale factor of 1/5 , centered at the origin.

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

Dilation is the reduction or enlargement in the size of an object by a scale factor (k). If k > 1, it is an enlargement and if k < 1, it is a reduction. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).

Therefore, if the vertices are dilated with a scale factor of 1/5 , centered at the origin. The new point is:

S(5, -10) → S′(1 , -2) T(10, -10) → T′(2 , -2) U(5, 10) → U′(1 , 2)

6 0
2 years ago
Read 2 more answers
Other questions:
  • Solve for x.
    6·1 answer
  • Ernesto drew a map of his school.He used a scale of 1 inch:50 feet.what distance in inches on Ernesto’s map should represent the
    5·1 answer
  • To make cheesecake you need about 21/2pounds of creamcheese how many pounds of cream cheese will you need to make 2 cheesecakes
    12·1 answer
  • What is (3x+12)-(6x+5)
    5·1 answer
  • Hii, Ok so basically I really need help with these questions they are really difficult and don't worry rewards are plenty a come
    7·1 answer
  • Can you solve this problem
    10·2 answers
  • Cooper invested $3,100 in an account paying an interest rate of 2%
    10·1 answer
  • WHAT in the valuE of 3n=1 when n=4?
    12·2 answers
  • Okok I'll try to get it myself but plssss help mee (brainliest)
    14·1 answer
  • Juan deposited $550 in an account that earned 2.5% simple interest. He did not make additional deposits and he didn't withdraw a
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!