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3 years ago

7

Please help due by 10:10!!!!!!!!!!

1 answer:

sertanlavr [38]3 years ago

4 0

Answer:

yes

Step-by-step explanation:

distributing gets you 8x+ 12= 2x-2 +6x+14

8x+12=8x+12

when both sides are simplified, they are equal to each other. This means that there IS a value of x that would make the perimeters equal

not sure what the drop down answers are so hope this helps

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Below are the steps to solve an equation:

otez555 [7]

Answer:

x-5=-3

Step-by-step explanation:

|x-5|+2=5

|x-5|=5-2

|x-5|=3

x-5=±3

so x-5=-3 is a correct step.

4 0

2 years ago

Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera

Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = $\frac{1}{2}(\text{Base})\times (\text{Height})$

Area of ΔADC = $\frac{1}{2}(\text{CD})(\text{AD})$

= $\frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})$

= $\frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)$

= $\frac{1}{2}(\sqrt{169-144})(12)$

= $\frac{1}{2}(5)(12)$

= 30 cm²

Area of equilateral triangle II = $\frac{\sqrt{3} }{4}(\text{Side})^2$

Area of equilateral triangle II = $\frac{\sqrt{3}}{4}(13)^2$

= $\frac{(1.73)(169)}{4}$

= 73.0925

≈ 73.09 cm²

Area of rectangle III = Length × width

= CF × CD

= 7 × 5

= 35 cm²

Area of trapezium EFGH = $\frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})$

Since, GH = GJ + JK + KH

17 = $\sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}$

12 = $\sqrt{81-x^2}+\sqrt{225-x^2}$

144 = (81 - x²) + (225 - x²) + 2 $\sqrt{(81-x^2)(225-x^2)}$

144 - 306 = -2x² + $2\sqrt{(81-x^2)(225-x^2)}$

-81 = -x² + $\sqrt{(81-x^2)(225-x^2)}$

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = $\frac{1}{2}(5+17)(9)$

= 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

= 237.09 cm²

7 0

3 years ago

Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ?

bearhunter [10]

Answer:

$\sf \log_{10}6=0.7781$

Step-by-step explanation:

<u>Given</u>:

$\sf \log_{10} 2 = 0.3010$

$\sf \log_{10} 3 = 0.4771$

To find log₁₀ 6, first rewrite 6 as 3 · 2:

$\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)$

$\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay$

$\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2$

Substituting the given values for log₁₀ 3 and log₁₀ 2:

$\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}$

Therefore:

$\sf \log_{10}6=0.7781$

Learn more about logarithm laws here:

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