5x = 4y - 3
Standard form is Ax + By = C, so first subtract 4y to both sides:
5x - 4y = -3
The answers are in the photo!
Answer:
B. 5
Step-by-step explanation:
Step 1: Rewrite the equation a bit
![\frac{7^\frac{3}{4}}{7^\frac{x}{8}}=\sqrt[8]{7}\\7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B7%5E%5Cfrac%7B3%7D%7B4%7D%7D%7B7%5E%5Cfrac%7Bx%7D%7B8%7D%7D%3D%5Csqrt%5B8%5D%7B7%7D%5C%5C7%5E%5Cfrac%7B3%7D%7B4%7D%5E-%5E%5Cfrac%7Bx%7D%7B8%7D%3D7%5E%5Cfrac%7B1%7D%7B8%7D)
Step 2: Place a logarithm base 7 on both sides

Step 3: Solve for x

Neat exponent question :)
The last one. THE PRODUCT OF 2 AND a PLUS 6.