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3 years ago

Help me with this question please.

Mathematics

1 answer:

Vlada [557]3 years ago

7 0

Answer:

The number of Pencils purchased and the cost of pencils represents a proportional relationship.

Step-by-step explanation:

As we know that proportional relationships between two variables have equivalent ratios.

For example,

3/12 = 9/36 is a TRUE proportions because both fractions reduces to 1/4, and because 12 × 9 = 3 × 36.

As our problem suggests whether the number of Pencils purchased and the cost of pencils represent a proportional relationship?

Given

Pencils $0.25 each

It means ach pencil costs $0.25.

If Sarah buys 1 pencil it would cost = $0.25

If Sarah buys 2 pencils it would cost = $0.5

If Sarah buys 3 pencils it would cost = $0.75

If Sarah buys 4 pencils it would cost = $1

Lets make a table:

No of Pencils Purchased Cost

1 $0.25

2 $0.5

3 $0.75

4 $1

Cost/No of Pencils Purchased = 0.25/1 = 0.5/2 = 0.75/3 = 1/4

So cost per pencil = 0.25 : 1

Since all of the ratios are equivalent, this table is a proportional relationship.

Therefore, the number of Pencils purchased and the cost of pencils represents a proportional relationship.

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Someone please hurry and help with number 4 and 6

makkiz [27]

Answer:

4.) y= 3x-2 6) y= 4

Step-by-step explanation:

m= 3 , (-2,-8)

y-(-8) = 3(x-(-2))

y+8= 3x+6

y= 3x-2

m= 0 , (5,4)

y- 4= 0(x-5)

y= 4

3 0

3 years ago

Read 2 more answers

Given circle and circle with radii of 6cm and 4cm respectively.

noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

$\angle EAF = \theta = 140^\circ$

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

= 14.653 cm

In circle C

$\angle GCH = \theta = 140^\circ$

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

= 9.769 cm

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is 1.5 times the length of GH

i.e. 14.653 = 1.5 x 9.769

14.653 = 14.653

Hence proved.

6 0

4 years ago

The answer has to be a geometric proof. Thank you!

Mariulka [41]

Given data:

The given triangle in which AD is on perpendicular bisector on BC.

In triangle ABD and ACD.

$\begin{gathered} \angle ADB=\angle\text{ADC}=90^{\circ} \\ BD=CD(\text{given)} \\ AD=AD\text{ (common)} \\ \Delta ABD\cong\Delta ACD(\text{SAS)} \end{gathered}$

Simmilary triangle BED and triangle CED.

$\begin{gathered} \angle BDE=\angle CDE \\ BD=CD \\ ED=ED \\ \Delta BED\cong\Delta CED(SAS) \end{gathered}$

The fisr expression can be written as,

$\begin{gathered} \Delta ABD\cong\Delta ACD \\ \Delta\text{ABE}+\Delta BED\cong\Delta ACE+\Delta\text{CED} \end{gathered}$

Substitute CED in place of BED.

$\begin{gathered} \Delta ABE+\Delta CED\cong\Delta ACE+\Delta CED \\ \Delta ABE\cong\Delta ACE \end{gathered}$

Thus, the triangle ABE is congruent to trriangle ACE.

7 0

1 year ago

If you flip a fair coin 4 times, what is the probability that you will get exactly 2 tails

Ilia_Sergeevich [38]

Answer:

<h3>The answer is <u>3/8</u> NOT 50%</h3>

Step-by-step explanation:

One way to solve this problem is to figure out how many ways you can get exactly 222 tails, then divide this by the total number of outcomes you could have gotten. Since every outcome has equal probability, this will be the probability that you will get exactly 2 tails.

How many outcomes are there where you get exactly 2 tails? Try thinking of each outcome as a 4-letter word, where the first letter is "H" if the first coin toss was heads and "T" if it was tails, and so on.

So, the number of outcomes with exactly 2 tails is the same as the number of these words which have 2 T's and 2 H's.

How many of these are there? If we treat all the letters as unique, we'll find that there are 4! different arrangements, overcounting 2! times for every time we only switch the T's around, and 2! times for every time we only switch the H's around.

So, there are <u>4!/2!2!</u> = 6

<u>4!/2!2!</u>= 6 different outcomes where you get exactly 2 tails.

Altogether, there are 2^4 = 16 total possible outcomes.

So, the probability that you will get exactly 2 tails is <u>6/16</u> = 3/8

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3 years ago

Find the linear equation from Slope of 4; y-intercept of - 5

Gemiola [76]

The general equation is y = mx + b where m is the slope and b is the y intercept

Therefore, substituting the numbers in;

y = 4x - 5

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3 years ago