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sergij07 [2.7K]
3 years ago
12

Type the correct answer in each box. Use numerals instead of words.

Mathematics
1 answer:
Flura [38]3 years ago
3 0

Answer:

The initial value of the boat was $20,000

The percent decrease per year of the value of the boat is 10%.

The interval on which the value of the boat is decreasing while Harry has it is (0,10)

Step-by-step explanation:

It is given that the boat costs $20,000 in 2010 when x = 0. So, the initial value of the boat was $20,000.

Next, find the percent decrease per year of the value of the boat. Consider the general form of an exponential equation, y = a(b)x, where a is the initial value of the boat, b is the base of the exponent, x is the number of years after 2010, and y is the value of the boat, in dollars.

Consider the point (1 , 18,000) which lies on the graph of this situation. Substitute x = 1, y = 18,000, and a = 20,000 into the exponential equation and isolate b.

Recall that for exponential decay, b = 1 - r where r represents the decay rate. Substitute b = 0.9 into this equation and solve for r.

So, the decay rate is 0.1, and the percent decrease per year of the value of the boat is 10%.

Harry bought the boat in 2010, and plans on selling it after 10 years in 2020. Therefore, the interval on which the value of the boat is decreasing while Harry has it is [0, 10].

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AysviL [449]

Answer: P(x ≥ 47) = 0.25

Step-by-step explanation:

Since the distribution of the life expectancies of a certain protozoan is normal, we would apply the formula for normal distribution which is expressed as

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Where

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From the information given,

µ = 46 days

σ = 10.5 days

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The probability that a simple random sample of 49 protozoa will have a mean life expectancy of 47 or more days is expressed as

P(x ≥ 47) = 1 - P(x < 47)

For x = 47

z = (47 - 46)/(10.5/√49) = 0.67

Looking at the normal distribution table, the probability corresponding to the z score is 0.0.75

P(x ≥ 47) = 1 - 0.75 = 0.25

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Step-by-step explanation:

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Step-by-step explanation:

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