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Vikki [24]
3 years ago
12

HELP ME PLEASE!!!!!!!!!!4(a+2)=8+4a

Mathematics
2 answers:
user100 [1]3 years ago
4 0
All real numbers are correct! Hope that helps.
Natasha2012 [34]3 years ago
4 0

Answer:

a can be anything. There are infinite solutions.

Step-by-step explanation:

4(a+2)=8+4a

Expand:

4a+4\times\:2=8+4a

4a+8=8+4a

Subtract 8 from both sides:

4a+8-8=8+4a-8

4a=4a

Subtract 4a from both sides:

4a-4a=4a-4a

0=0

Since both sides are equal, a has infinite solutions as no matter what value it is, it will not affect the end result of 0=0 which is true.

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Find the domain when f (x) = 5.<br> х<br> -5<br> -1<br> 9<br> 4<br> 5<br> 8<br> f(x) -6<br> -6 | 0
nadezda [96]

Answer:

Pues la función de 5 seria 4 porque si te fijas en la X es (4)

5 0
3 years ago
What is the slope of the line that passes through the points (10,5)and (15,20)
kupik [55]

Answer:

<h2>The answer is 3</h2>

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

m =  \frac{ y_2 - y _ 1}{x_ 2 - x_ 1}  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(10,5)and (15,20)

The slope is

m =  \frac{20 - 5}{15 - 10}   =  \frac{15}{5}  = 3 \\

We have the final answer as

<h2>3</h2>

Hope this helps you

8 0
3 years ago
Given that no additional deposits are made ,compare the balances of the two accounts after 10years? ( Round to the nearest dolla
andre [41]

Answer:

I want the 8 points ty ty

Step-by-step explanation:

ty for the 8 points I really really appreciate it and also heart my comment ty!

7 0
2 years ago
Find the sum (3x^2+5x-8)+(5x^2-13x-5)
Radda [10]
<span>8x^2-8x-13 is the correct answer </span>
3 0
3 years ago
Read 2 more answers
Graph y= x−2.<br> PLZZ HELP
nataly862011 [7]

Explanation: To graph the equation y = x - 2, the idea is simple.

We pick three values for <em>x</em>, plug them into the

equation, and find the corresponding values for <em>y</em>.

In order to do this in an organized way, we set up a chart.

Down the left side we make a column for our x's, down the right side we make a column for our y's, and in the middle we make a column for the side of the equation that contains the <em>x</em>, in this case, x - 2.

So reading the chart from left to right, we have our <em>x</em> or what we plug into the equation, then we have the x - 2 or what happens to the x when we plug it into the equation, and finally we have our <em>y</em> or what we end up with after plugging <em>x</em> into the equation.

So our first step in filling out the chart is choosing

the x's that we want to plug into the equation.

When graphing lines, I always choose three x's,

a positive number, zero, and a negative number.

The easiest numbers to pick are usually 1, 0, and -1.

So for 1, we plug a 1 into the equation for <em>x</em>

and we have y = (1) - 2 or -1

For 0 we plug a 0 into the equation for <em>x</em>

and we have y = (0) - 2 or -2.

For -1 we plug a -1 into the equation for <em>x</em>

and we have y = (-1) - 2 or -3.

So our points are (1, -1), (0, -2), and (-1, -3).

I looked at the x and y column to find those points.

Since our domain is all real numbers, we can connect these points based on the pattern that they are forming on the graph which is a line.

5 0
3 years ago
Read 2 more answers
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