Find the area of the parallelogram with vertices Ps1, 0, 2d, Qs3, 3, 3d, Rs7, 5, 8d, and Ss5, 2, 7d.
1 answer:
You might be interested in
Option B:
25 degrees
Solution:
Given data in triangle PQR,
The side opposite to angle P is p.
The side opposite to angle Q is q.
The side opposite to angle R is r.
q = 36, r = 20, angle Q = 50°.
<u>To find the measure of angle R:</u>
Using law of sine,
Take only two sides.
Substitute the given values.
Do cross multiplication.
sin 50° = 0.766
⇒ R = 25.18°
⇒ R = 25° (approximately)
Option B is the correct answer.
Hence the measure of angle R is 25 degrees.