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seropon [69]
3 years ago
5

Which complex number will be plotted below the real axis and to the right of the imaginary axis?

Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0
<h3>Answer: B) 4 - i</h3>

============================================

Explanation:

Any complex number is in the form a+bi which visually can be plotted at the point (a,b). Treat 'a' as 'x', and think of 'b' as 'y'. So (a,b) = (x,y).

a = real part of the number, so because a = x, this means the "real axis" is the x axis.

b = imaginary part of the number, so b = y means the "imaginary axis" is the y axis.

-----------------

The statement "below the real axis" indicates the point is below the x axis, so y < 0 and b < 0.

The portion "to the right of the imaginary axis" tells us the point has a positive x coordinate, so x > 0 and a > 0

With a > 0 and b < 0, the only thing that fits is a+bi = 4 + (-1)i = 4-i. In this case, a = 4 and b = -1.

Below is an attached image showing all of the answer choices plotted on the same xy coordinate grid. Only the second answer choice is in the proper region we want.

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4 0
3 years ago
What are the vertical asymptote(s) of y= (x-6)/(x+8) (x-7)
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Answer:

x = -8 and x= 7

Step-by-step explanation:

recall that for a rational expression, the vertical asymptotes occur at x-values that causes the expression to become undefined. These occur when the denominator becomes zero.

Hence the asymptototes will occur in x-locations where the denominator , i.e

(x+8)(x-7) = 0

solving this, we get

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or

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hence the asymptotes occur x = -8 and x= 7

5 0
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7 0
3 years ago
Need help with this math problem
Andre45 [30]

Hey There!

First you would need to factor out the two.

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-2x^3+x^2+6x+3 / x+1

We would then factor with polynomial division, and then we should have.

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Hope this helped!

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Answer:

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