For this case we have that by definition, the line equation of the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
According to the statement we have:

Thus, the equation is of the form:

We substitute the given point and find "b":

Finally, the equation is of the form:

Answer:

In order to get the figure, you have to plot it.
Quadlirateral ABCDwith <span>vertices: A(-4, -3), B(2, -3), C(4, -6), and D(-4, -6) is </span>s A. TRAPEZOID
We have to determine the equation of the line passing through the point (2,-5) and parallel to the line 
When two lines are parallel, then the slopes of the two lines are equal.
Equation of line with point
and slope 'm' is given by:

Since, we have to determine the equation of a line with point (2,-5).
So, the equation of the line is : 

Since, the line is parallel to the line 
So, 


So, slope of the line 'm' is
.
Therefore, the equation of the line is:




Therefore,
is the required equation of the line.
1cm *10 = 10km
40cm * 10 = 400 km
50km/50 = 1cm
400km/50 = 8cm
A: 8cm
Answer:
15 - 3 x 5
cbhojwj fn h bf be be gwtt sa ta ets e
Step-by-step explanation:15