All categories

3 years ago

Help?...............................

Mathematics

1 answer:

STALIN [3.7K]3 years ago

8 0

Is it 57? ...............................

You might be interested in

Mr.smith and mr.Stein We’re driving to a business meeting 100 miles from their office. Mr.smith Drove the first y miles ,then mr

Reptile [31]

Answer:

mrs smith drove 50 miles and mr stein drove 50 mile

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the total service area of this cone. leave your answer in terms of pi. r=10in h=24in

daser333 [38]

Answer:

36pie inch²

Step-by-step explanation:

Answer attached

Hope it helps :)

5 0

2 years ago

Bob paid $54 for shoes if they were on sale for 10% off what was the original price

PIT_PIT [208]

Bob paid $48.6 that’s the total

8 0

2 years ago

Liza wants to have more than $750 in her savings account before she will leave for college. Right now she has $300, and she is g

Kazeer [188]

She will need a minimum of 38 hours, at 38 hours she will make 456, plus the 300 she already has, so that in total is 756.

6 0

3 years ago

A study showed that 25% of the students drive themselves to school. Based on the suggested probability, in a class of 18 student

Gwar [14]

Answer:

B) 0.283

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

25% of the students drive themselves to school.

This means that $p = 0.25$

Class of 18 students

This means that $n = 18$

What would be the probability that at least 6 students drive themselves to school?

This is

$P(X \geq 6) = 1 - P(X < 6)$

In which

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.25)^{0}.(0.75)^{18} = 0.006$

$P(X = 1) = C_{15,1}.(0.25)^{1}.(0.75)^{17} = 0.034$

$P(X = 2) = C_{15,2}.(0.25)^{2}.(0.75)^{16} = 0.096$

$P(X = 3) = C_{15,3}.(0.25)^{3}.(0.75)^{15} = 0.17$

$P(X = 4) = C_{15,4}.(0.25)^{4}.(0.75)^{14} = 0.213$

$P(X = 5) = C_{15,5}.(0.25)^{5}.(0.75)^{13} = 0.199$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.006 + 0.034 + 0.096 + 0.17 + 0.213 + 0.199 = 0.718$

$P(X \geq 6) = 1 - P(X < 6) = 1 - 0.718 = 0.282$

Closest option is B, just a small rounding difference.

4 0

3 years ago