Answer:
- construct PQ
- construct circles of radius PQ centered at P and Q
- label one of the points of intersection R
- Construct PR and QR
Step-by-step explanation:
You should actually do this some time. It will help you understand the construction process and help you remember the steps. It may even help you figure out why it works.
5.5/4=x/100
4x=550
x=137.5
the water tower is 137 ft. 6 in. tall.
Split up the interval [0, 2] into 4 subintervals, so that
![[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]](https://tex.z-dn.net/?f=%5B0%2C2%5D%3D%5Cleft%5B0%2C%5Cdfrac12%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac12%2C1%5Cright%5D%5Ccup%5Cleft%5B1%2C%5Cdfrac32%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac32%2C2%5Cright%5D)
Each subinterval has width 
. The area of the trapezoid constructed on each subinterval is 
, i.e. the average of the values of 
at both endpoints of the subinterval times 1/2 over each subinterval ![[x_i,x_{i+1}]](https://tex.z-dn.net/?f=%5Bx_i%2Cx_%7Bi%2B1%7D%5D)
.
So,
Answer:
Step-by-step explanation:
608 square inches
Answer:
D
Step-by-step explanation:
Current coordinate of R : ( 1,5 )
Applying translation with rule (x,y) --> (x+1 , y-1)
Coordinate after translation ( 1 , 5 ) ==> ( 1 + 1 , 5 - 1 ) ==> ( 2 , 4 )
applying dilation with scale factor of 3 , to apply dilation multiply x and y values by scale factor which is 3
Coordinate after dilation ( 2 , 4 ) ==> ( 2 × 3 , 4 × 3 ) ==> ( 6 , 12 )
The final coordinate is ( 6 , 12 )
