Complete the objective function. P = x + y

a train goes 20% farther than an older train in the same amount of time. During the time it takes the other train to go 200 mile

MakcuM [25]

Answer:

240 miles

Step-by-step explanation:

To solve this we need to write an equation. For this problem let d be the distance traveled. We know that the new train (being much more modern than poor old Thomas who is long retired) can go 20% further. To show this we will take 20% of 200 and then add that to the original distance.

Our equation would look something like this:

d=200+(20%·200)

[one more little note: to find percentage take your percent and convert it into a decimal 20%=0.2)

d=200+(0.2·200)

d=200+40

d=240

4 0

3 years ago

Solve for z -p(d+z)=-2z+59

suter [353]

Distribute
-pd-pz=-2z+59
add 2z both sides
-pd-pz+2z=59
add pd to both sides
-pz+2z=59+pd
2z-pz=59+pd
undistribute z
z(2-p)=59-pd
divide bot sides by 2-p
$z=\frac{59-pd}{2-p}$
$z=\frac{pd-59}{p-2}$

7 0

3 years ago

For the following hypothesis test, determine the null and alternative hypotheses. Also, classify the hypothesis test as two-tail

bagirrra123 [75]

Answer:

Option B:

$H_0: \mu = 22.1$

$H_a: \mu \neq 22.1$

Classification:

The hypothesis test is Two-tailed.

Step-by-step explanation:

The mean length of imprisonment for motor-vehicle theft offenders in this country is 22.1 months.

This means that the null hypothesis is that the mean is of 22.1 months, that is:

$H_0: \mu = 22.1$

A hypothesis test is to be performed to determine whether the mean length of imprisonment for motor-vehicle theft offenders in this city differs from the national mean of 22.1 months.

At the alternate hypothesis, we test if this mean is different of 22.1, that is:

$H_a: \mu \neq 22.1$

Which means that the answer is given by option b).

Which of the following is the correct classification of the hypothesis test?

We test if the mean is different from a value, which means that the hypothesis test is Two-tailed.

7 0

3 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

so

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

2 years ago

In which step did Viet make an error?

Yuri [45]

Answer:

Step 1

Step-by-step explanation:

When moving the 4 to the other side, Viet was supposed to subtract 4 from each side, leaving 0 on the left, and 102-4 on the other side. 102-4=98, not 106. Viet added when he was supposed to subtract.

8 0

3 years ago