Answer:
plz mark me as brsinliest..
Answer:
yes you can
apart from getting rid of the denominator you can collect like terms
Step-by-step explanation:
d=6-3/5
6=30/5
30/5-3/5
27/5
d=27/5
Y=a(x-h)^2+k
is what vertex form look like. (h,k) is your vertex so in this problem your vertex would be (60,200)
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
