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Rufina [12.5K]
3 years ago
14

The length of a rectangle is 4 yd longer than its width. If the perimeter of the rectangle is 48 yd, find its area.

Mathematics
1 answer:
bagirrra123 [75]3 years ago
7 0
48 = 2(w+4) + 2w
48 = 4w+8
40 = 4w
w= 10 yd
A= 10 * 14
A = 140 yd
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(18×2) + 2n=58
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Which two values of X are roots of the polynomial below 4x^2-6x+1
PtichkaEL [24]

4x^2-6x+1=0\\\\a=4,\ b=-6,\ c=1\\\\\Delta=b^2-4ac\\\\\Delta=(-6)^2-4(4)(1)=36-16=20\\\\\sqrt\Delta=\sqrt{20}=\sqrt{4\cdot5}=\sqrt4\cdot\sqrt5=2\sqrt5\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a},\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-(-6)-2\sqrt5}{2\cdot4}=\dfrac{3-\sqrt5}{4}\\\\x_2=\dfrac{-(-6)+2\sqrt5}{2\cdot4}=\dfrac{3+\sqrt5}{4}

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Help me out! (URGENT) I need help with numbers 1-6 please
Alex Ar [27]

Answer:

Step-by-step explanation:

1. Blank= 5

2. Blank= 10 (I believe)

3. Blank= 8

4. Blank= 13 (I believe)

5. Blank= 12

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What vaule of x makes th question true? 3x+2(x-5)=50 a. 8 b.9 c.11 d.12
Ainat [17]
Hey Tierra7l, 

Lets solve your equation together step by step. 

3x+2\left(x-5\right)=50 

\mathrm{Expand}\:2\left(x-5\right):\quad 2x-10 

\mathrm{Distribute\:parentheses\:using}:\quad \:a\left(b+c\right)=ab+ac 

                                    a=2,\:b=x,\:c=-5 

2\cdot \:x+2\left(-5\right) 

\mathrm{Apply\:minus-plus\:rules} 

\:\:+\left(-a\right)=-a 

2x-2\cdot \:5 

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:5=10 

2x-10 

3x+2x-10=50 

\mathrm{Add\:similar\:elements:}\:3x+2x=5x 

5x-10=50 

\mathrm{Add\:}10\mathrm{\:to\:both\:sides} 

5x-10+10=50+10 

\mathrm{Simplify} 

5x=60 

\mathrm{Divide\:both\:sides\:by\:}5 

\dfrac{5x}{5}=\dfrac{60}{5} 

\mathrm{Simplify} 

x=12 

Hope this helps, 

      AnthrαX <span>  </span>
4 0
3 years ago
Need someone to help me
Softa [21]
The answer to this question is B!
8 0
3 years ago
Read 2 more answers
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