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wolverine [178]
3 years ago
9

There are 230 calories in a 48 g packet of M\& M's. How many calories are in a 72 g bag?

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0

Answer:

345 calories are in a 72g bag

Step-by-step explanation:

48/2=24

48+24=72

230/2=115

230+115=345

NNADVOKAT [17]3 years ago
5 0

Answer:

346 calories

Step-by-step explanation:

230 needs to be divided by 48 to find the unit rate. 4.8 calories per gram is found. This number is multiplied by the grams of the second bag to find it contains about 345.6 which can be rounded to 346

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A clock tower has a large bell that rings on the hour. The edge of the bell has a diameter of 4 yards. What is the edge's radius
bezimeni [28]

Answer:

4

Step-by-step explanation:

4 times 1 is 4 <em><u>Also</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>multiplying</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>most</u></em><em><u> </u></em><em><u>common</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>times</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>average</u></em><em><u> </u></em><em><u>volume</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>most</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>get</u></em><em><u> </u></em><em><u>4</u></em>

3 0
3 years ago
The coefficient for 2(3)(6)Q is
Bad White [126]
The answer to this is 36

8 0
3 years ago
F(x)=2x^2-x-6 g(x)=4-x (f+g)(x)
Semenov [28]

\large  \boxed{(f + g)(x) = f(x) + g(x)}

The property above is distribution property where we distribute x-term in the function.

Substitute both f(x) and g(x) in.

\large{ \begin{cases} f(x) = 2 {x}^{2}   -  x - 6 \\ g(x) =  4 - x \end{cases}}  \\  \large{f(x) + g(x) = (2 {x}^{2}  - x - 6) + (4 - x)} \\  \large{f(x) + g(x) = 2 {x}^{2}  - x - 6 + 4 - x}

Évaluate/Combine like terms.

\large{f(x)  + g(x) = 2 {x}^{2}  - 2x - 2}

The function can be factored so there are two answers. (Both of them work as one of them is factored form while the other one is not.)

\large{(f + g)(x) = 2 {x}^{2}  -2x -2}

<u>Alternative</u>

\large{(f + g)(x) = 2({x}^{2}  -x - 1)}

<u>Answer</u>

  • (f+g)(x) = 2x²-2x-2
  • (f+g)(x) = 2(x²-x-1)

Both answers work. The second answer is in factored form.

Let me know if you have any doubts!

8 0
2 years ago
Can someone help me?
svlad2 [7]

Answer:

Use Pythagorean theorem,

Hypotenuse² = base² + altitude²

= 3²+ 6²

= 9 + 36

x² = 45

x = √45

x = 6.71

Step-by-step explanation:

7 0
3 years ago
The diameter of steel rods manufactured on two different extrusion machines is being investigated. Two random samples of sizes
devlian [24]

Answer:

(a) There is no evidence to support the claim that the two machines produce rods with different mean diameters.

P-value is 0.818

(b) 95% confidence interval for the difference in mean rod diameter is (-0.17, 0.27).

This interval shows that the difference in mean is between -0.17 and 0.27.

Step-by-step explanation:

(a) Null hypothesis: The two machines produce rods with the same mean diameter.

Alternate hypothesis: The two machines produce rods with different mean diameter.

Machine 1

mean = 8.73

variance = 0.35

n1 = 15

Machine 2

mean = 8.68

variance = 0.4

n2 = 17

pooled variance = [(15-1)0.35 + (17-1)0.4] ÷ (15+17-2) = 11.3 ÷ 30 = 0.38

Test statistic (t) = (8.73 - 8.68) ÷ sqrt[0.38(1/15 + 1/17)] = 0.05 ÷ 0.218 = 0.23

degree of freedom = n1+n2-2 = 15+17-2 = 30

Significance level = 0.05 = 5%

Critical values corresponding to 30 degrees of freedom and 5% significance level are -2.042 and 2.042.

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.23 falls within the region bounded by the critical values -2.042 and 2.042.

There is no evidence to support the claim that the two machines produce rods with different mean diameters.

Cumulative area of test statistic is 0.5910

The test is a two-tailed test.

P-value = 2(1 - 0.5910) = 2×0.409 = 0.818

(b) Difference in mean = 8.73 - 8.68 = 0.05

pooled sd = sqrt(pooled variance) = sqrt(0.38) = 0.62

Critical value (t) = 2.042

E = t×pooled sd/√n1+n2 = 2.042×0.62/√15+17 = 0.22

Lower limit of difference in mean = 0.05 - 0.22 = -0.17

Upper limit of difference in mean = 0.05 + 0.22 = 0.27

95% confidence interval for the difference in mean rod diameter is between a lower limit of -0.17 and an upper limit of 0.27.

3 0
3 years ago
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