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Klio2033 [76]
2 years ago
7

The area of a square is 484 square inches. How long is each side?

Mathematics
2 answers:
hodyreva [135]2 years ago
8 0

Answer:

\sqrt{484} =22

Step-by-step explanation:

levacccp [35]2 years ago
7 0
Each side is 21 square inches.

The formula for area of a square is:

A=a^2

So to find the area from that you would replace the area (484 sq. in) for A and solve.

a^2=484

Square root on both sides and you’re left with.

a=21
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There are 8 dinosaur eggs in a nest. Each egg weighs 48 ounces. How many pounds do all the eggs in the nest weigh together?
victus00 [196]

Answer:

Step-by-step explanation:

No of eggs in a nest = 8

Weight of egg= 48ounces

Total weight = 48 x 8 = 384 ounces

1 ounce = 0.0625 pounds

384 ounce = 24 pounds

24 pounds is the correct answer

4 0
2 years ago
Read 2 more answers
Rewrite using a single positive exponent
fiasKO [112]

Step-by-step explanation:

\frac{ {7}^{4} }{7}  =  {7}^{4 - 1}  =  {7}^{3}

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3 years ago
Find the Area of the figure below, composed of a rectangle and one semicircle, with another semicircle removed. Round to the nea
iren [92.7K]

Answer:

  72 square units

Step-by-step explanation:

The figure shown has a uniform horizontal cross section, so is equivalent to a rectangle with length 12 and height 6. Its area is given by the rectangle formula:

  A = LW

  A = (12)(6) = 72 . . . . square units

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<em>Additional comment</em>

Essentially, the semicircle removed from the left side is tacked onto the right side. The rectangle area is unchanged by that.

5 0
2 years ago
A football field measures 300 feet in length. It can also be expressed as approximately 5 7x 10miles. If the
kogti [31]

Answer:

The question is incomplete or there are details missing.

Step-by-step explanation:

From similar parameters, if by what they mean is that the football field measures 300feet in length, which is the dimension in length, this can also be in terms of metre.

The conversion factor between ft and metre is 1ft = 0.3048m

As such, we can only have variations or the length of the field measured may have ranges of measurement,  but as it is the length of the field can not be expressed in terms of miles, the most reasonable vale of n we can get will be the least measurement in metres.

3 0
3 years ago
Jan wants to protect the wooden box in question 4a by painting varnish on all of the outside surfaces, including the bottom. Wil
Dafna1 [17]

Answer:

As this question is incomplete, but we will try to solve this question by adding our own data to understand the concept of the problem.

Explanation is given below

Step-by-step explanation:

As this question is incomplete, but we will try to solve this question by adding our own data to understand the concept of the problem.

In order to answer this question we need to have the dimensions of the box.

Let's suppose there are 6 outside surfaces of the box and are equal in dimension including the bottom side which Jan wants to varnish.

So,

Let's suppose,

Surface area of the cube = 6a^{2}

Here, Surface area = 275 square inch

Surface area of the cube = 6a^{2} = 275 square inch

a^{2} = 275/6 = 45.833

a = \sqrt{45.833}

a = 6.77 inches

Now, for the amount of the varnish, we need the spreading rate of the varnish to be used on the box,

Let's suppose it is = 11 square incher per litre.

So,

Required Varnish = Surface area / Spreading rate

Required varnish = 275 / 11

Required varnish = 25 liters

If the 1 container of varnish contains 25 liters then it will be sufficient to protest the outside surfaces of the box.

6 0
3 years ago
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