The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
Answer:no
Step-by-step explanation:it would not be possible as 8 is a larger number then 3 unless u would be multiplying by decimals which in which case might be possible
Answer:
Answer: C) The mean will increase more than the median, but both will increase.
Step-by-step explanation:
I got it right on the test review.
-2y>12x-42
y<21-6x
so a is true
Answer:
think one
Step-by-step explanation:
DO IT USING THINK ONE