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makvit [3.9K]
2 years ago
9

Please help due asap

Mathematics
1 answer:
Nadusha1986 [10]2 years ago
4 0
Answer:5
Explanation:Pythagorean Theorem
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Which would be the best method to use to solve the following equations? Explain your reasoning.
o-na [289]

A. square root property

3x^2-192=0\\x^2-66=0\\x^2=66\\x= -\sqrt{66} or \sqrt{66}

it has one value with x which is x^2 and it cn be easily solved without having to factorise, quadratic formula cant be used as it need ax^2+bx+c=0 format

B. factorising

x^2-x-6=0\\x^2+2x-3x-6=0\\(x+2)(x-3)=0\\x+2=0  and  x-3=0\\x= -2 \\x= 3

i just felt like this was easier to factorise than the other 2 options left

C. Completing the square

x^2-6x-7=0\\(x-3)^2=0\\x= -1\\x= 7

same reason personal preference

D- Quadratic

x^2-17x-7=0\\x=\frac{-(-17)+\sqrt{(-17)^2-4(1)(-7)} }{2(1)} \\x=\frac{-(-17)-\sqrt{(-17)^2-4(1)(-7)} }{2(1)}\\x=17.4\\x=-0.402

the 17 kinda threw me off and i didnt wanna get on factorising or doing completing the square so quadratic formal

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What are the instructions or equations to use
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torisob [31]

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Step-by-step explanation:

For the problem, \sqrt[3]{24} *\sqrt[3]{45}, use rules for simplifying cube roots. Under the operations of multiplication and division, if the roots have the same index (here it is 3) you can combine them.

\sqrt[3]{24} *\sqrt[3]{45} = \sqrt[3]{24*45}

You can multiply it out completely, however to simplify after you'll need to pull out perfect cubes. Factor 24 and 45 into any perfect cube factors which multiply to each number. If none are there, then prime factors will do. You can group factors together such as 3*3*3 which is 27 and a perfect cube.

\sqrt[3]{24*45} =\sqrt[3]{3*8*5*3*3}  = 6 \sqrt[3]{5}

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Find the constant of proportionality
kirill115 [55]

Answer:

the constant of proportionality is 3. thank me later : )

Step-by-step explanation:

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