Answer:
35 ia the answer sorry if im wrong
Hopefully this helped! I used the substitution method
You can graph this two ways. You can change it into slope intercept form, y=mx+b, or find the x- and y-intercepts. To change it to slope intercept form you would need to add 12x to both sides and divide both sides by 18. By doing this, you'd get y=2/3x+17/9. You'd then go up on the y-axis to 17/9 or 1.89 and place a point. You'd then go up two and to the right three and place another point. You can do this one more time and connect the points. To find the x- and y- intercepts you would plug 0 in for x and solve for y, getting 17/9, and plug 0 in for y and solve for x, getting -17/6. You'd then plot the points (-17/6, 0) and (17/9) and connect the points forming a line.
Answer:
The answer is
<h2>(9x - 4)(4x + 3)</h2>
Step-by-step explanation:
36x² + 11x - 12
To factor the expression rewrite 11x as a difference
That's
36x² + 27x - 16x - 12
<u>Factor out 9x from the expression</u>
9x( 4x + 3) - 16x - 12
<u>Factor out - 4 from the expression</u>
9x( 4x + 3) - 4( 4x + 3)
Factor out 4x + 3 from the expression
We have the final answer as
<h3>(9x - 4)(4x + 3)</h3>
Hope this helps you
Answer:
95% z-confidence interval for the proportion of all children enrolled in kindergarten who attended preschool is between a lower limit of 0.528 and an upper limit of 0.772.
Step-by-step explanation:
Confidence interval = p + or - zsqrt[p(1-p) ÷ n]
p is sample proportion = 39/60 = 0.65
n is the number of children sampled = 60
Confidence level (C) = 95% = 0.95
Significance level = 1 - C = 1 - 0.95 = 0.05
Divide significance level by 2 to obtain critical value (z)
0.05/2 = 0.025 = 2.5%
z at 2.5% significance level = 1.96
zsqrt[p(1-p) ÷ n] = 1.96sqrt[0.65(1-0.65) ÷ 60] = 1.96sqrt[0.2275 ÷ 60] = 1.96sqrt(3.792×10^-3) = 1.96×0.062 = 0.122
Lower limit = p - 0.122 = 0.65 - 0.122 = 0.528
Upper limit = p + 0.122 = 0.65 + 0.122 = 0.772
95% confidence interval is between 0.528 and 0.772
